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3 years ago

What is the acceleration of an object with a mass of 367 kg when a net force of 183 N is applied to it

Physics

1 answer:

GarryVolchara [31]3 years ago

4 0

Answer:

mass=367kg

force=183N

acceleration =?

Now,

force=m×a

183=367×a

183÷367=a

0.49=a

acceleration =0.49m/s^2 answer!!!!

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Explanation:

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2 years ago

A seesaw is 4.0m long with a pivot at its midpoint. A boy who weighs 400N sits at a distance of 1.5m from the pivot. His sister

bezimeni [28]

Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

Explanation:

Given;

length of the seesaw, L = 4.0 m

weight of the boy, W₁ = 400 N

position of the boy from the pivot, d₁ = 1.5 m

weight of her sister, W₂ = 300 N

First, make a sketch of this information given;

0---0.5m---------------------Δ--------------------------4m

↓<--------1.5m-------> <---------x--------->↓

400 N 300N

Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

x = 600/300

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3 years ago

A car moved 60 meters west in 2 hours. What is its average velocity?

Fofino [41]

Explanation: Velocity is the displacement of an object during a specific unit of time. Two measurements are needed to determine velocity. Displacement and time. Displacement includes a direction, so velocity also includes a direction. Speed with direction. Velocity can be an average velocity or an instantaneous velocity. Units for velocity are the same as for speed: m/s, km/h, and mph. Delta x(Δx) is the symbol used for displacement. Delta (Δ) means to "change in." Δx means to "change in position." Δx is calculated by final position minus initial position. Velocity formula: → v=Δx/t as a fraction.

v=Δx/t

$v=\frac{xf-xi}{t}= \frac{60m}{2}=30m$

Final answer is 30.

Hope this helps!

Thanks!

Have a great day!

-Charlie

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3 years ago