1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
matrenka [14]
3 years ago
7

What is the acceleration of an object with a mass of 367 kg when a net force of 183 N is applied to it

Physics
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

mass=367kg

force=183N

acceleration =?

Now,

force=m×a

183=367×a

183÷367=a

0.49=a

acceleration =0.49m/s^2 answer!!!!

You might be interested in
A computational model predicts the maximum kinetic energy a roller coaster car can have given its mass, the speed at the highest
Ymorist [56]

Answer:

D

Explanation:

The decrease in potential energy is equal to the increase in kinetic energy.

mgh

250 x 9.8 x 30

=73, 500

3 0
3 years ago
Calculate the momentum of a 6 kg rock that is rolling down a hill with a velocity of 4 m/s.
Leokris [45]

Answer:

24kgm/s

Explanation:

momentum(p)=mass×velocity

=6×4

=24 kgm/s

4 0
3 years ago
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
eduard
Uhh? Do you have any questions or need help?
7 0
3 years ago
Read 2 more answers
A square loop of wire lies in the x, y plane with opposite corners at (0, 0) and (a, a). The loop carries a current I directed t
Ket [755]

Answer:

Please refer to the figure.

Explanation:

The magnitude of the magnetic field can be found by Biot-Savart Law. We should divide the loop into four components. Each component has a similar solution but their directions are quite different.

The directions can be found by right-hand rule. Point your index finger into the direction of current, point your middle finger towards the target point (0,0,a). Your thumb will show you the direction of magnetic field.

5 0
3 years ago
A yo‑yo with a mass of 0.0800 kg and a rolling radius of =2.70 cm rolls down a string with a linear acceleration of 5.70 m/s2.
N76 [4]

Explanation:

Given that,

Mass, m = 0.08 kg

Radius of the path, r = 2.7 cm = 0.027 m

The linear acceleration of a yo-yo, a = 5.7 m/s²

We need to find the tension magnitude in the string and the angular acceleration magnitude of the yo‑yo.

(a) Tension :

The net force acting on the string is :

ma=mg-T

T=m(g-a)

Putting all the values,

T = 0.08(9.8-5.7)

= 0.328 N

(b) Angular acceleration,

The relation between the angular and linear acceleration is given by :

\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{5.7}{0.027}\\\\=211.12\ m/s^2

(c) Moment of inertia :

The net torque acting on it is, \tau=I\alpha, I is the moment of inertia

Also, \tau=Fr

So,

I\alpha =Fr\\\\I=\dfrac{Fr}{\alpha }\\\\I=\dfrac{0.328\times 0.027}{211.12}\\\\=4.19\times 10^{-5}\ kg-m^2

Hence, this is the required solution.

3 0
3 years ago
Other questions:
  • In _______ atomic model, negative electrons orbit the positively charged nucleus.
    9·2 answers
  • A handle or knob is fixed at free end of door.why?
    8·1 answer
  • How are forest fires beneficial to conifers like Jack Pines? a. Jack pine seeds are protected by forest fires. b. Pine cones are
    8·2 answers
  • Sediments are deposited in an alluvial fan because __________________________________________
    12·1 answer
  • A 500 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 30 N/m. The blo
    5·1 answer
  • 4 points
    10·1 answer
  • Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to
    10·1 answer
  • At least how many Calories does a mountain climber need in order to climb from sea level to the top of a 5.42 km tall peak assum
    13·1 answer
  • Assume that a vaulter is able to carry a vaulting pole while running as fast as Carl Lewis in his world record 100-m dash (aroun
    13·1 answer
  • The process by which solids vaporize without first becoming a liquid is called.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!