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3 years ago

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Chemistry

2 answers:

emmainna [20.7K]3 years ago

6 0

Answer:

the answer to this question here is A

Explanation:

trust me

valkas [14]3 years ago

5 0

Answer:

Acid and Salt

Explanation:

Common hydrogen compounds

Hydrogen combines with other elements, forming a number of compounds, including common ones such as water (H2O), ammonia (NH3), methane (CH4), table sugar (C12H22O11), hydrogen peroxide (H2O2) and hydrochloric acid (HCl), according to Jefferson Lab.

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Find the fugacity coefficient of a gaseous species of mole fraction 0.4 and fugacity 25 psia in a mixture at a total pressure of

Oksana_A [137]

Answer: The fugacity coefficient of a gaseous species is 1.25

Explanation:

Fugacity coefficient is defined as the ratio of fugacity and the partial pressure of the gas. It is expressed as $\bar{\phi}$

Mathematically,

$\bar{\phi}_i=\frac{\bar{f_i}}{p_i}$

Partial pressure of the gas is expressed as:

$p_i=\chi_iP$

Putting this expression is above equation, we get:

$\bar{\phi}_i=\frac{\bar{f_i}}{\chi_iP}$

where,

$\bar{\phi}_i$ = fugacity coefficient of the gas

$\bar{f_i}$ = fugacity of the gas = 25 psia

$\chi_i$ = mole fraction of the gas = 0.4

P = total pressure = 50 psia

Putting values in above equation, we get:

$\bar{\phi}_i=\frac{25}{0.4\times 50}\\\\\bar{\phi}_i=1.25$

Hence, the fugacity coefficient of a gaseous species is 1.25

8 0

3 years ago

You are confronted by a phosphorus atom. this atom has 15 protons and 17 neutrons. how many electrons does it have

bogdanovich [222]

15 electrons if it is not an ion

8 0

3 years ago

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Calculate the oxidation numbers of the elements in this equation 2 Al2O3 → 4 Al + 3 O2

riadik2000 [5.3K]

Explanation:

Answer

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The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.

Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O ) = 0

2× ( Oxidation number of Al) +3(−2)=0

2× ( oxidation number of Al) +6

∴ Oxidation number of Al =+3

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3 years ago

If the temperature of an object is 335K,how would his be expressed on the celsius scale ?

IRISSAK [1]

335K would be expressed as 61.85 degrees Celsius

3 0

4 years ago

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In which of the following reactions does a decrease in the volume of the reaction vessel at constant

Black_prince [1.1K]

Answer:

The correct option is: A) 2H₂(g) + O₂(g) → 2H₂O(g)

Explanation:

According to the Le Chatelier's principle, change in the volume of the reaction system causes equilibrium to shift in the direction that reduces the effect of the volume change.

When the volume decreases then the pressure of the reaction vessel increases, then the equilibrium shifts towards the reaction side that produces less number of moles of gas.

A) 2H₂(g) + O₂(g) → 2H₂O(g)

The number of moles of reactant is 3 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the product side, thereby favoring the formation of products.

B) NO₂(g) + CO(g) → NO(g) + CO₂(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

C) H₂(g) + I₂(g) → 2HI(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

D) 2O₃(g) → 3O₂(g)

The number of moles of reactant is 2 and number of moles of product is 3.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

E) MgCO₃(s) → MgO(s) + CO₂(g)

The number of moles of reactant is 1 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

6 0

3 years ago