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grandymaker [24]
3 years ago
7

Convert the boiling temperature at gold, 2966 degree centigrate , into degrees fahrenheit and kelvin.

Chemistry
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

Boiling point of gold is 1630 ^{0}\textrm{F} or 3239.15 K

Explanation:

We know, T(^{0}\textrm{F})=1.8T(^{0}\textrm{C})+32

Here T(^{0}\textrm{C}) and T(^{0}\textrm{F}) are temperature in degree centigrate and temperature in degree farhenite respectively.

So, 2966^{0}\textrm{C}=\frac{2966-32}{1.8}^{0}\textrm{F}

                                            = 1630 ^{0}\textrm{F}

We know, 1^{0}\textrm{C}=273.15 K

So, 2966 ^{0}\textrm{C} = (2966+273.15) K = 3239.15 K

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‼️SHOW ALL STEPS‼️ If 14.4 grams of iron reacts with hydrochloric acid, how many grams of hydrogen gas will be produced?
Alex Ar [27]

Answer: 0.771 g of H_2 will be produced

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe=\frac{14.4g}{56g/mol}=0.257moles

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2Fe(s)+6HCl(aq)\rightarrow 2FeCl_3(aq)+3H_2(g)  

According to stoichiometry :

2 moles of Fe produce = 3 moles of H_2

Thus 0.257 moles of Fe will produce=\frac{3}{2}\times 0.257=0.385moles  of H_2  

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3 0
3 years ago
The solubility of two slightly soluble salts of M^2+ , MA and MZ_2, are the same, 4 x 10^â4 mol/L.
LekaFEV [45]

Answer:

a) MZ₂

b) They have the same concentration

c) 4x10⁻⁴ mol/L

Explanation:

a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.

The salts solubilization reactions and their Kps values are:

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Thus, the Kps of MZ₂ has a larger value.

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7 0
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Thus percentage of s-character in an sp hybrid is 50%.

8 0
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