How many oxygen molecules are in 22.4 liters of oxygen gas
at 273k and 101.3kpa
First solve the number of moles of the oxygen gas by using
the ideal gas equation:
PV = nRT
Where n is the number of moles
n = PV/RT
n = (101 300 Pa) (22.4 L) (1 m3/1000 L ) / ( 8.314 Pa m3 /
mol K) ( 273 K)
n = 1 mol O2
the number of molecules can be solve using avogrados number
6.022x10^23 molecule / mole
molecules of one mole O2 = 6.022x 10^23 molecules
Explanation:
at rest the pulse rate will be so hard to detect while after rest it will be so easy to read the pulse I guess.
The answer would be a mixture. A mixture is when two or more substances are combined to create heterogeneous mix, where the substances do not combine with each other in an equal or even state, but just sit together.
Molecule C requires the least energy, Molecule B requires more, and Molecule A requires the most.
Explanation:
Molecule C is made up of a triple bond, which requires the most energy to break. Molecule B is made up of a double bond which is not as strong as a triple bond therefore requiring less energy. Molecule A is made up of a single bond which is the least strong thus requiring the least amount of energy.
