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MAXImum [283]
4 years ago
10

How many moles of lithium hydroxide are required to react with 19.2 mol CO2, the average amount exhaled by a person each day?

Chemistry
1 answer:
sladkih [1.3K]4 years ago
3 0

Answer:

38.4 mol LiOH

Explanation:

Step 1: Write the balanced neutralization equation

2 LiOH + CO₂ ⇒ Li₂CO₃ + H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of LiOH to CO₂ is 2:1.

Step 3: Calculate how many moles of lithium hydroxide are required to react with 19.2 mol CO₂

19.2 mol CO₂ × 2 mol LiOH / 1 mol CO₂ = 38.4 mol LiOH

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gizmo_the_mogwai [7]
This is what I would use. Hopefully this helps:)

3 0
3 years ago
Read 2 more answers
If a 100.-g sample of platinum metal has a volume of 4.67 ml, what is the density of platinum in g/cm3?
Mariulka [41]
The density of any substance does not change at a certain temperature and pressure. Even though mass and volume are intensive properties (depends on the amount of substance), density is not. It is merely a fixed ratio of mass to volume. Therefore, the solution is

Density = Mass/Volume
For your information, quantitatively, cm³ is equivalent to mL.
Density = 100 g/4.67 cm³ = 21.41 g/cm³
7 0
4 years ago
Given the balanced ionic equation representing the reaction in an operating voltaic cell: zn(s) + cu2+(aq) → zn2+(aq) + cu(s) th
soldi70 [24.7K]

Answer: from the Zn anode to the Cu cathode


Justification:


1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)


2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).


3) Then, you can already tell that electrons go from Zn to Cu.


4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.


So you get that the electrons flow from the anode (Zn) to the cathode (Cu).


Always oxidation occurs at the anode, and reduction occurs at the cathode.

3 0
4 years ago
Calculate the molarity of a solution prepared by dissolving 12.5 g of Na2CrO4 in enough water to produce a solution with a volum
gregori [183]

Answer:

0.0953M

Explanation:

First, let us calculate the number of mole present in 12.5g of Na2CrO4.

Molar Mass of Na2CrO4 = (23x2) + 52 +(16x4) = 46 + 52 +64 = 162g/mol

Mass of Na2CrO4 = 12.5g

Number of mole =?

Number of mole =Mass /Molar Mass

mole of Na2CrO4 = 12.5/162 = 0.0772mol

Now, we can calculate for the molarity as follows:

Mole = 0.0772mol

Volume = 810mL = 810/1000 = 0.81L

Molarity =?

Molarity = mole /Volume

Molarity = 0.0772mol/0.81L

Molarity = 0.0953M

4 0
3 years ago
What is the chemical formula of diphosphorus monoxide?
Daniel [21]

Answer:

The chemical formula of diphosphorus monoxide is OP2.

I'm not sure if this is correct, but hope it helps! :)

7 0
3 years ago
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