B, they belong to group 1
A: Li is period 2 and Na is period 3
C: Na has one more electron shell
D: Not related to how it is spelled
Answer:
p = 1.5 atm
Explanation:
pV = nRT
p = nRT/V = [1.8 mol×(0.082 atm L/mol K)×247.8 K]/24.5 L
p = 1.5 atm
Answer:
31.24 kJ
Explanation:
- SiO₂(g) + 3C(s) → SiC(s) + 2CO(g) ΔH° = 624.7 kJ/mol
First we <u>convert 3.00 grams of SiO₂ to moles</u>, using its <em>molar mass</em>:
- 3.00 g SiO₂ ÷ 60.08 g/mol = 0.05 mol
Now we <u>calculate the heat absorbed</u>, using the <em>given ΔH°</em>:
If the complete reaction of 1 mol of SiO₂ absorbs 624.7 kJ, then with 0.05 mol:
- 0.05 mol * 624.7 kJ/mol = 31.24 kJ of heat would be absorbed.
