Ask question

Ask question

All categories

GenaCL600 [577]

3 years ago

7

PHYSICS HW PLS HELP I DONT UNDERSTAND

1 answer:

PIT_PIT [208]3 years ago

6 0

Do you still need help with it??

You might be interested in

Twopucksofequalmasscollideonafrictionlesssurface,asillustratedinthefigure.Immediatelyafterthe collision, the speed of the black

seropon [69]

Answer:

The speed of the white puck immediately after the collision is 2.6 m/s.

Explanation:

Given that,

Two pucks are equal masses.

Speed of black puck = 1.5 m/s

According to given figure,

We need to calculate the speed of the white puck immediately after the collision

Using law of conservation of momentum

$mv=m_{1}v_{1}\cos\theta+m_{2}v_{2}\cos\theta$

Put the value into the formula according to figure

$m\times3=m\times v_{1}\times\cos30+m\times1.5\times\cos60$

$3m=0.866m v_{1}+0.75m$

$v_{1}=\dfrac{3-0.75}{0.866}$

$v_{1}=2.6\ m/s$

Hence, The speed of the white puck immediately after the collision is 2.6 m/s.

8 0

3 years ago

_____ is the densest planet. Mercury Venus Earth Mars

Orlov [11]

The answer is Venus, with the density of 5.204 grams per cubic centimeter

5 0

3 years ago

A +15 nC point charge is placed on the x axis at x = 1.5 m, and a -20 nC charge is placed on the y axis at y = -2.0m. What is th

IceJOKER [234]

Answer: $E=75\ N/m$

Explanation:

Given

First charge of $q_1=15\ nC$ is placed at $x=1.5\ m$

Second charge $q_2=-20\ nC$ is placed at $y=-2\ m$

Electric field is given by

$E=\frac{kq}{r^2}$

Electric field due to $q_1$ is away from it

$E_1=\frac{9\times 10^9\times 15\times 10^{-9}}{(1.5)^2}$

$E_1=60\ N/m$

Electric field due to $q_2$

$E_2=\frac{9\times 10^9\times 20\times 10^{-9}}{2^2}$

$E_2=45\ N/m$

Net electric field will be vector addition of two

$\vec{E_{net}}=\vec{E_1}+\vec{E_2}$

$\vec{E_{net}}=-60\hat{i}-45\hat{j}$

Magnitude of Electric field is

$E=\sqrt{60^2+45^2}$

$E=75\ N/m$

8 0

3 years ago

Kepler's laws, satellites motion and weightlessness

Anon25 [30]

Answer:

First Kepler law states that <em><u>Each</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>describes</u></em><em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>ellipsoidal</u></em><em><u> </u></em><em><u>motion</u></em><em><u> </u></em><em><u>about</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>sun</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>its</u></em><em><u> </u></em><em><u>single</u></em><em><u> </u></em><em><u>focus</u></em><em><u>.</u></em>

Second Kepler law states that <em><u>A</u></em><em><u>n</u></em><em><u> </u></em><em><u>i</u></em><em><u>m</u></em><em><u>a</u></em><em><u>g</u></em><em><u>i</u></em><em><u>n</u></em><em><u>a</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>l</u></em><em><u>i</u></em><em><u>n</u></em><em><u>e</u></em><em><u> </u></em><em><u>j</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>i</u></em><em><u>n</u></em><em><u>g</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>t</u></em><em><u>o</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>Sun</u></em><em><u> </u></em><em><u>sweeps</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>areas</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>time</u></em><em><u> </u></em><em><u>intervals</u></em><em><u>.</u></em>

Third Kepler law states that <em><u>The</u></em><em><u> </u></em><em><u>squares</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>period</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>revolution</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>around</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>sun</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>proportional</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>cubes</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>mean</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>sun</u></em><em><u>.</u></em>

Weightlessness is the condition where the body has zero gravity ( its acceleration is equal to the acceleration due to gravity )

$.$

3 0

3 years ago

How to make a force field for your house

Lelu [443]

That is not yet possible. that technology has not yet been invented.

6 0

3 years ago