What is the acceleration due to gravity at an altitude of 116?
1 answer:
Gravitational acceleration (Ga) is inversely proportional to k / Distance^2
so Ga * Distance^2 = K
On the surface of Earth acceleration due to gravity is about 9.8m/s^2 with an average distance to the earths core of about 6371 km (Wolfram alpha).
So k = 9.8 * 6371^2
I'm presuming that your distance of 116 is km
As
Ga = k / distance^2
Ga = ((9.8 * 6371^2) / (6371 + 116)^2 ) = 397778481.8 / 42081169
= 9.45 m/s^2 to 2sf
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Explanation:
∆x=300 m×2
∆t=1.5 s
v=∆x/∆t → v=2×300/1.5 = 400 m/s
Answer:
75m/s
Explanation:
...................
Explanation:
Given:
v₀ = 0 m/s
v = 49 m/s
a = 9.8 m/s²
Find: t
v = at + v₀
49 m/s = (9.8 m/s²) t + 0 m/s
t = 5 s
Your answer is 632,100J which is Choice D