Just add all of them up and there is your answer I just added it but I want u to work it out to..
If the period of a satellite is T=24 h = 86400 s that means it is in geostationary orbit around Earth. That means that the force of gravity Fg and the centripetal force Fcp are equal:
Fg=Fcp
m*g=m*(v²/R),
where m is mass, v is the velocity of the satelite and R is the height of the satellite and g=G*(M/r²), where G=6.67*10^-11 m³ kg⁻¹ s⁻², M is the mass of the Earth and r is the distance from the satellite.
Masses cancel out and we have:
G*(M/r²)=v²/R, R=r so:
G*(M/r)=v²
r=G*(M/v²), since v=ωr it means v²=ω²r² and we plug it in,
r=G*(M/ω²r²),
r³=G*(M/ω²), ω=2π/T, it means ω²=4π²/T² and we plug that in:
r³=G*(M/(4π²/T²)), and finally we take the third root to get r:
r=∛{(G*M*T²)/(4π²)}=4.226*10^7 m= 42 260 km which is the height of a geostationary satellite.
The correct option is: Option (D) 1.0T Out of the page.
Explanation:
The formula for the induced emf in the wire = ε = Blv
ε = Potential difference = 1.0 V
v = speed of the wire = 10 m/s
l = length of the wire = 10cm = 0.1 m
B = magnetic field = ?
Plug in the values:
B = ε/lv = 1/(0.1*10) = 1 T (And according to the right hand rule it should be out of the page.)
