A cylinder with initial volume V contains a sample of gas at pressure p. On one end of the cylinder, a piston is let free to mov
1 answer:
Answer:
The work done on the gas = 2PV
Explanation:
In this question, we need to apply the basic gas laws to determine the word done.
For this question, we need to draw a PV diagram (a pressure-volume diagram), which I have made and attached in the attachment. So please refer to that attachment. I will be using this diagram to solve for the work done on the gas.
So, Please refer to the attachment number 1. where x -axis is of volume and y-axis is of pressure.
As we know that, the work done on the gas is equal to the area under the curve.
W = Area of the triangle
W = 0.5 x ( base) x ( height)
W = 0.5 x (BC) x (AC)
W = 0.5 x (3V-V) x (3P-P)
W = 2PV
Hence, the work done on the gas = 2PV
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Answer:
The value is
Explanation:
From the question we are told that
The initial velocity of the proton is
At a distance R from the nucleus the velocity is
The velocity considered is
Generally considering from initial position to a position of distance R from the nucleus
Generally from the law of energy conservation we have that
Here is the change in kinetic energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
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And is the change in electric potential energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
Here is zero because the electric potential energy at the initial stage is zero so
So
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Generally considering from initial position to a position of distance from the nucleus
Here represented the distance of the proton from the nucleus where the velocity is
Generally from the law of energy conservation we have that
Here is the change in kinetic energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
=>
=>
=>
And is the change in electric potential energy from initial position to a position of distance
from the nucleus , this is mathematically represented as
Here is zero because the electric potential energy at the initial stage is zero so
So
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Divide equation 2 by equation 1
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Answer:
1. The displacement is 427.2 km.
Explanation:
1. A = 150 km North
B = 400 km East
The net displacement is given by