Which one of the following compounds shows red precipitate of Cu2O with the reaction of Fehling solution?

Chemistry

1 answer:

Fiesta28 [93]3 years ago

3 0

Answer:

acetaldehyde

When acetaldehyde is heated with Fehling's solution, a red precipitate is formed.

Explanation:

You might be interested in

Trying to explain why a cactus needs little water to survive is an example of

zmey [24]

It’s a or b i think it’s b

6 0

3 years ago

The line graph shows the heights of plants grown in fertilized and unfertilized soil. Based on this information, what will most

AfilCa [17]

Answer:

g) Neither plant should increase by 1 cm in height.

Explanation:

See the graph for this question on the figure attached.

The growing of the plant A is represented by the line that goes above the other. At start, that line has a slope that rises about 0.75 cm ( height increase) in 1 day. From the day 2 and forward the slope of the line decreases. The line reaches its highest point about at day 4 and seems to start decreasing. Thus, you should predict that on the day six it most likely does not increase in height.

The growing of the plant B is represented by the line drawn below the other. As for the plant B, the growing decreases with the number of days. Between the days 4 and 5 the line is almost flat, which means that most likely this plant will not grow on the day six or grow less than 0.5 cm.

Thus, for both plants you can say that on day six, most likley, neither should increase by 1 cm in height (option g).

4 0

3 years ago

Describe the physical properties of each state of matter

Leni [432]

Solid - made up of tightly packed particles, which gives it a solid shape.
Gas - made up of very loose particles, giving it more freedom to roam around as a gas
Liquid - fills into whatever it gets put in, basically takes the shape of the object its in

6 0

4 years ago

PLEASE HELP!!!! WILL MARK BRAINLIEST!!!! A rigid steel container with a volume of 30 L is filled with oxygen to a pressure of 9.

GuDViN [60]

Answer:

12 atm

Explanation:

First, let us convert Celcius into Kelvin: 28.0 °C = 301.15 K and 129.0 °C = 402.15 K

For this question we must employ the Combined Gas Law: $\frac{P_1V_1}{P_2V_2}=\frac{n_1RT_1}{n_2RT_2}$ , where $P_1$ is the initial pressure and $P_2$ is the new pressure.

We know that intitially, P=9 atm, V=30 L, and T=301.15K. From our problem, only temperature and pressure changes, while the number of moles, volume and the gas constant, R, stay the same, so they are irrelevant.

Thus, the filled out Combined Gas Law would be:

$\frac{9 atm}{P_2}$ = $\frac{301.15K}{402.15K}$ , where the volume, moles of gas, and R are cancelled out.