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kkurt [141]
2 years ago
11

For a particular reaction, ΔH = -99.84 kJ and ΔS = -16.80 J/K. Calculate ΔG for this reaction at 298 K.

Chemistry
1 answer:
marta [7]2 years ago
7 0
To solve this given problem,  we can use the equation below:
ΔG=ΔH - T*ΔS

We are information and values are given and can be used in solving the ΔG of this particular reaction.
ΔH=-99.84kJ
ΔS=-16.80 J/K
T=298K

ΔG=(-99.84kJ)-(298K*-16.80J/K)
ΔG=-94.83kJ

The answer for ΔG is -94.83kJ.
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The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins
saul85 [17]
The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
So, we know:
t = 10 min
<span>t_{1/2} = 2.5 min

We need:
n = ?
x = ?
</span>
We could first use the second equation to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{10 min}{2.5 min}
⇒ n=4<span>
</span>
Now we can use the first equation to calculate the remained fraction of the sample.
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3 0
3 years ago
The psychoactive drug sold as a methamphetamine - "speed" (c10h15n) - undergoes a series of reactions in the body; the net resul
Phoenix [80]

Answer: The coefficient of nitrogen in the given equation is 2.

Explanation: The reaction for the oxidation of methamphentamine with oxygen gas in the body is given by:

4C_{10}H_{15}N(s)+55O_2(g)\rightarrow 40CO_2(g)+30H_2O(l)+2N_2(g)

By Stoichiometry,

4 moles of methamphentamine reacts with 55 moles of oxygen gas to produce 40 moles of carbon dioxide gas, 30 moles of water and 2 moles of nitrogen gas.

Coefficient of C_{10}H_{15}N=4

Coefficient of O_2=55

Coefficient of CO_2=40

Coefficient of H_2O=30

Coefficient of N_2=2

Hence, the coefficient of nitrogen in the given equation is 2.

8 0
2 years ago
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