Answer:
c = 0.898 J/g.°C
Explanation:
1) Given data:
Mass of water = 23.0 g
Initial temperature = 25.4°C
Final temperature = 42.8° C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of water is 4.18 J/g°C
ΔT = 42.8°C - 25.4°C
ΔT = 17.4°C
Q = 23.0 g × × 4.18 J/g°C × 17.4°C
Q = 1672.84 j
2) Given data:
Mass of metal = 120.7 g
Initial temperature = 90.5°C
Final temperature = 25.7 ° C
Heat released = 7020 J
Specific heat capacity of metal = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25.7°C - 90.5°C
ΔT = -64.8°C
7020 J = 120.7 g × c × -64.8°C
7020 J = -7821.36 g.°C × c
c = 7020 J / -7821.36 g.°C
c = 0.898 J/g.°C
Negative sign shows heat is released.
M(AgNO₃) = 169.9 g; mass.
n(AgNO₃) = m(AgNO₃) ÷ M(AgNO₃).
n(AgNO₃) = 169.9 g ÷ 169.87 g/mol.
n(AgNO₃) = 1 mol; amount of silver nitrate.
c(AgNO₃) = 1 M = 1 mol/L.
V(AgNO₃) = n(AgNO₃) ÷ c(AgNO₃).
V(AgNO₃) = 1 mol ÷ 1 mol/L.
V(AgNO₃) = 1 L.
V(AgNO₃) = 1 L · 1000 mL/L.
V(AgNO₃) = 1000 mL; volume of silver nitrate.
Answer:
2 moles
Explanation:
Hi there !!
Given volume = 44.8 litres
Molar volume = 22.4 litres
No: of moles = Given volume / Molar volume
= 44.8 / 22.4 = 2 moles
Answer:
there is your answer hope it helped :3
This problem is very easy to answer. You simply have to look at the subscripts of each element of the compound.
1. For caffeine, which has a molecular formula of C₈H₁₀N₄O₂, it contains 8 atoms of Carbon, 10 atoms of Hydrogen, 4 atoms of Nitrogen and 2 atoms of Oxygen.
2. For Iron(III) Sulfate, which has a molecular formula of Fe₂(SO₄)₃, it contains 2 atoms of Iron, 3 atoms of Sulfur, and 12 atoms of Oxygen.