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EastWind [94]
3 years ago
10

Un recipiente contiene una capa de aceite (densidad 600 kg/m³) de 17.1 cm, sobre otra de agua (densidad 1000 kg/m³) de 28.4 cm d

e espesor. ¿Qué presión hidrostática hay en el fondo del recipiente?
Physics
1 answer:
MAVERICK [17]3 years ago
5 0

Answer:

P=3792.55 Pa

Explanation:

Para resolver este problema, vamos primero a hacer un dibujo de la situación (ver imagen adjunta).

En este caso, tanto el peso del aceite como el peso del agua están ejerciendo una  presión sobre el fondo del recipiente, por lo que la presión total será la suma de ambas presiones. La presión está dada por la equación:

P=\rho gh

por lo que la presión total será:

P_{total}=P_{aceite}+P_{agua}

P_{total}=\rho _{aceite} gh_{aceite}+\rho _{agua} gh_{agua}

y sustituímos (mucho cuidado de convertir las alturas a metros)

P_{total}=(600 kg/m^{3})(9.81 m/s^{2})(17.1x10^{-2}m)+(1000 kg/m^{3}) (9.81 m/s^{2})(28.4x10^{-2}m)

lo cual nos da como resultado:

P=3792.55 Pa

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Explanation:

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