If matter was not composed of atoms, the law definite proportions and law of multiple proportions will not hold true because compound would have random composition.
<h3>What is the law of definite proportions and law of multiple proportions?</h3>
The law of definite proportions states that all pure samples of a compound contains the same element in a fixed mass ratio.
The law of multiple proportions states that if an element combines with another element to form more than one compound, the mass of the element combines with a fixed mass of the other element in whole number multiples ratios.
Assuming matter was not composed of atoms, the law definite proportions and law of multiple proportions will not hold true because, their will be no definite ratio or composition in compounds.
The law definite proportions and law of multiple proportions are required for the atomic theory as they help prove that matter consists of definite unique particles called atoms.
In conclusion, the existence of atoms is proved true by the law definite proportions and law of multiple proportions.
Learn more about law of multiple proportions at: brainly.com/question/2624012
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Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles
Answer:
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1) Write the balanced chemical equation
4NH3 + 5O2 ----> 4NO + 6H2O
2) Write the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Write the proportions with the desired quantity of NO and the unknown quantity of O2
5 mol O2 / 4 mol NO = x / 18.0 mol NO
Solve for x: x = 18.0 mol NO * 5 mol O2 / 4 mol NO = 22.5 mol O2
4) Use the ideal gas equation to convert moles to volume
pV = nRT => V = nRT / p
n = 22.5 mol
R = 0.082 atm*liter / K * mol
T = 33 + 273.15 = 306.15 K
p = 874/760 atm = 1.15 atm
V = 22.5 mol * 0.082 atm*liter/K*mol * 306.15 K / 1.15 atm = 491.17 liter
Answer: 491 liters of O2
Answer:
the volume will decrease
Explanation:
an increase in temperature will lead to an increase in effective collision which also result in an increase in volume, when the temperature decreases, the volume will decrease
