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pogonyaev
3 years ago
12

What is Lewis acid and Lewis base? give examples​

Chemistry
1 answer:
AleksAgata [21]3 years ago
6 0

Explanation:

example is copper iron...........

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Plz help will mark as brainliest <br><br>CHOOSE THE CORRECT ANSWER ​
kodGreya [7K]

Answer:

1. Is red blood cells

2. Is high pressure

Explanation:

In the atrium deoxygenated blood is pumped

8 0
3 years ago
What is the mass of 1.2 mol IrI3?​
mr_godi [17]

Answer:

690 g IrI₃

Explanation:

To convert from moles to grams, you have to use the molar mass of the compound. The molar mass of IrI₃ is 572.92 g/mol. You use this as the unit converter in this equation:

1.2molIrI3 * \frac{572.92g}{1mol} = 687.504 g IrI3

Round to the lowest number of significant figures which is 2 to get 690 g IrI₃.

5 0
3 years ago
Read the given equation. 2Na + 2H2O → 2NaOH + H2
Crank

Answer:

B) 12.9 grams.

Explanation:

How many moles of molecules in that 6.30 L of H₂?

The volume of one mole of an ideal gas at STP (0 °C, 1 atm) is 22.4 liters.

(The volume of that one mole of gas at STP will be 22.7 liters if STP is defined as 0 °C and 10⁵ Pa).

\displaystyle n(\text{H}_2) = \frac{6.30\;\text{L}}{22.4\;\text{L}\cdot\text{mol}^{-1}} = 0.28125\;\text{mol}.

How many moles of Na will be needed?

The coefficient in front of Na in the equation is twice the coefficient in front of H₂. It takes two moles of Na to produce one mole of H₂.

n(\text{Na}) = 2\;n(\text{H}_2) = 2\times 0.28125= 0.5625\;\text{mol}.

What's the mass of that many Na atoms?

Refer to a modern periodic table. The molar mass of ₁₁Na is 22.990. The mass of one mole of Na atoms is 22.990 gram. The mass of 0.5625 moles of Na atoms will be

m = n\cdot M = 0.5625 \times 22.990 = 12.9\;\text{g}.

(2 sig. fig. as in the volume of the H₂ gas.)

6 0
3 years ago
How do subscripts represent the charge balance of ions
finlep [7]
<h3><u>Answer and explanation</u>;</h3>
  • To balance the charges of ions the number of electrons lost is equal to the number of electrons gained. The overall net charge must be zero.
  • The number of ions needed to accomplish this is represented by the subscripts.
  • For any given ionic compound, the product of the charge on the ion (or multiatomic ionic group) times the subscript of the ion will give a total charge of zero when all ions are considered.

For examples: NaCl Na = +1 Cl = -1 total is zero

5 0
4 years ago
Calculate the standard molar enthalpy of formation, in kJ/mol, of NO(g) from the following data:
Paraphin [41]

The above question is incomplete, here is the complete question:

Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o= -114.1 kJ

Answer:

The standard molar enthalpy of formation of NO is 90.25 kJ/mol.

Explanation:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o_{1} = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o_{2} = -114.1 kJ

To calculate the standard molar enthalpy of formation

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?...[3]

Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

[1] - [2] = [3]

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?

\Delta H^o_{3} =\Delta H^o_{1} - \Delta H^o_{2}

\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ

According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :

=\frac{\Delta H^o_{3}}{2 mol}

=\frac{180.5 kJ}{2 mol}=90.25 kJ/mol

3 0
3 years ago
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