Answer:
1. Is red blood cells
2. Is high pressure
Explanation:
In the atrium deoxygenated blood is pumped
Answer:
690 g IrI₃
Explanation:
To convert from moles to grams, you have to use the molar mass of the compound. The molar mass of IrI₃ is 572.92 g/mol. You use this as the unit converter in this equation:

Round to the lowest number of significant figures which is 2 to get 690 g IrI₃.
Answer:
B) 12.9 grams.
Explanation:
How many moles of molecules in that 6.30 L of H₂?
The volume of one mole of an ideal gas at STP (0 °C, 1 atm) is 22.4 liters.
(The volume of that one mole of gas at STP will be 22.7 liters if STP is defined as 0 °C and 10⁵ Pa).
.
How many moles of Na will be needed?
The coefficient in front of Na in the equation is twice the coefficient in front of H₂. It takes two moles of Na to produce one mole of H₂.
.
What's the mass of that many Na atoms?
Refer to a modern periodic table. The molar mass of ₁₁Na is 22.990. The mass of one mole of Na atoms is 22.990 gram. The mass of 0.5625 moles of Na atoms will be
.
(2 sig. fig. as in the volume of the H₂ gas.)
<h3><u>Answer and explanation</u>;</h3>
- To balance the charges of ions the number of electrons lost is equal to the number of electrons gained. The overall net charge must be zero.
- The number of ions needed to accomplish this is represented by the subscripts.
- For any given ionic compound, the product of the charge on the ion (or multiatomic ionic group) times the subscript of the ion will give a total charge of zero when all ions are considered.
For examples: NaCl Na = +1 Cl = -1 total is zero
The above question is incomplete, here is the complete question:
Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:


Answer:
The standard molar enthalpy of formation of NO is 90.25 kJ/mol.
Explanation:


To calculate the standard molar enthalpy of formation
...[3]
Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[1] - [2] = [3]


![\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7B3%7D%3D66.4%20kJ%20-%20%5B%20-114.1%20kJ%5D%20%3D%20180.5%20kJ)
According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :
=
