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Licemer1 [7]
3 years ago
15

Help please I don’t know

Chemistry
1 answer:
Tema [17]3 years ago
8 0
I believe it’s the last one

Hope this helped
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Calculate the ph for each case in the titration of 50.0 ml of 0.150 m hclo(aq) with 0.150 m koh(aq). use the ionization constant
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<h3><u>Answer</u>;</h3>

pH =7.58

<h3><u>Explanation;</u></h3>

The KOH will react with the HClO to produce KClO. You will have a solution containing unreacted HClO and KOH. This is a buffer solution.  

Equation:  

HClO + KOH → KClO + H2O  

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Mol KOH in 30mL of 0.150M solution = 30/1000*0.150 = 0.0045 mol KOH  

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