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uranmaximum [27]
3 years ago
6

Pls answer this I will mark u as the brainliest...what is the formula of sodiam carbonate ​

Chemistry
2 answers:
kodGreya [7K]3 years ago
8 0

Explanation:

Sodium Carbonate = Na2CO3

Hope it helps ya

cestrela7 [59]3 years ago
6 0

Answer:

The answer is Na2CO3.

- Sodium carbonate = Na2CO3

- It is used as an antacid to treat heartburn, indigestion, and upset stomach. Sodium bicarbonate is a very quick-acting antacid.

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I think it's conduction.
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3 years ago
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Which of the following salts would be more soluble in acidic solution? A. KNO3 B. CaF2 C. AgCl D. Pbl2
slega [8]

Answer:

CaF2

Explanation:

Because HF is a weak acid, fluoride salts behave as bases in aqueous solution. As a Lewis base, F– accepts a proton from hydronium, which is transformed into a water. Picture is attached.

4 0
3 years ago
Given the following equation: 4 Fe + 3022 Fe2O3 What mass of iron is needed
icang [17]

Answer : The mass of iron needed is 29.5 grams.

Explanation : Given,

Mass of O_2 = 12 g

Molar mass of O_2 = 32 g/mol

First we have to calculate the moles of O_2.

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}

\text{Moles of }O_2=\frac{12g}{32g/mol}=0.375mol

Now we have to calculate the moles of Fe

The balanced chemical equation is:

4Fe+3O_2\rightarrow 2Fe_2O_3

From the reaction, we conclude that

As, 3 moles of O_2 react with 4 moles of Fe

So, 0.375 mole of O_2 react with \frac{4}{3}\times 0.375=0.5 mole of Fe

Now we have to calculate the mass of Fe

\text{ Mass of }Fe=\text{ Moles of }Fe\times \text{ Molar mass of }Fe

Molar mass of Fe = 59 g/mole

\text{ Mass of }Fe=(0.5moles)\times (59g/mole)=29.5g

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8 0
4 years ago
What is the percent by mass of C in benzene (C6H6)? The molecular weight of carbon is 12.0107 g/mol and of hydrogen 1.00794 g/mo
pshichka [43]

Answer:

92.26% of C

Explanation:

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Mass atom / Total mass * 100

<em>Mass C: </em>6mol C * (12.0107g / mol) = 72.0642g

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<em>total mass: </em>72.0642g + 6.04764g = 78.11184g

Mass percent of C will be:

72.0642g C / 78.11184g* 100

<h3>92.26% of C</h3>

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