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masha68 [24]
3 years ago
14

g A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 3.00 m at constant speed. If the coe

fficient of kinetic friction between the desk and the floor is 0.400, how much work did she do
Physics
1 answer:
Rainbow [258]3 years ago
6 0

The desk is in equilbrium, so Newton's second law gives

∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0

∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0

==>   <em>n</em> = <em>mg</em>

==>   <em>p</em> = <em>f</em> = <em>µn</em> = <em>µmg</em> = 0.400 (80.0 kg) <em>g</em> = 313.6 N

The student pushes the desk 3.00 m, so she performs

<em>W</em> = (313.6 N) (3.00 m) = 940.8 Nm ≈ 941 J

of work.

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Answer:

due to production of heat through friction

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3 years ago
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Every sample of a pure substance has exactly the same composition and the same properties. true or false
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False, that does not apply to some

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Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed o
love history [14]

Answer:

13.51 nm

Explanation:

To solve this problem, we are going to use angle approximation that sin θ ≈ tan θ ≈ θ where our θ is in radians

y/L=tan θ ≈ θ

and ∆θ ≈∆y/L

Where ∆y= wavelength distance= 2.92 mm =0.00292m

L=screen distance= 2.40 m

=0.00292m/2.40m

=0.001217 rad

The grating spacing is d = (90000 lines/m)^−1

=1.11 × 10−5 m.

the small-angle

approx. Using difraction formula with m = 1 gives:

mλ = d sin θ ≈ dθ →

∆λ ≈ d∆θ = =1.11 × 10^-5 m×0.001217 rad

=0.000000001351m

= 13.51 nm

6 0
3 years ago
Martina seems to have several different personalities. In one, she is 7 years
melomori [17]

Answer:Dissociative Identity Disorder

Explanation:I don't say you have to mark my ans brainliest but my friend if it has really helped you don't forget to thank me...

3 0
4 years ago
What is the energy of a photon whose frequency is 6.0 x 10^20?
omeli [17]

Answer:

3.75 MeV

Explanation:

The energy of the photon can be given in terms of frequency as:

E = h * f

Where h = Planck's constant

The frequency of the photon is 6 * 10^20 Hz.

The energy (in Joules) is:

E = 6.63 x10^(-34) * 6 * 10^(20)

E = 39.78 * 10^(-14) J = 3.978 * 10^(-13) J

We are given that:

1 eV = 1.06 * 10^(-19) Joules

This means that 1 Joule will be:

1 J = 1 / (1.06 * 10^(-19)

1 J = 9.434 * 10^(18) eV

=> 3.978 * 10^(-13) J = 3.978 * 10^(-13) * 9.434 * 10^(18) = 3.75 * 10^(6) eV

This is the same as 3.75 MeV.

The correct answer is not in the options, but the closest to it is option C.

6 0
3 years ago
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