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JulijaS [17]
2 years ago
13

A wind turbine designer is considering installing a horizontal axis wind turbine at a location in Michigan. To increase the powe

r extracted from wind, the designer is debating between increasing the blade radius by 10% versus increasing the height from 40 m to 60 m, which would increase the average wind speed from 6 mph to 6.5 mph. Considering the only the impact on power extraction, the designer should go with the height increase.
a. True
b. False
Engineering
1 answer:
bogdanovich [222]2 years ago
3 0

Answer:

False ( B )

Explanation:

considering that the wind turbine is a horizontal axis turbine

Power generated/extracted by the turbine can be calculated as

P =  n * 1/2 *<em> p</em> *Av^3

where: n = turbine efficiency

           <em>p = air density </em>

<em>            </em>A = πd^2 / 4

           v =  speed

From the above equation it can seen that increasing the Blade radius by 10% will increase the Blade Area which will in turn increase the value of the power extracted by the wind turbine

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Select the properties and typical applications for the high carbon steels.
yanalaym [24]

Answer:

<u>Option-(A)</u>

Explanation:

<u>Typical applications for the high carbon steels includes the following;</u>

It is heat treatable, relatively large combinations of mechanical characteristics. Typical applications: railway wheels and tracks, gears, crankshafts, and machine parts.

3 0
3 years ago
A part made from annealed AISI 1018 steel undergoes a 20 percent cold-work operation. Obtain the yield strength and ultimate str
Charra [1.4K]

Answer:

yield strength before cold work = 370 MPa

yield strength after cold work = 437.87 MPa

ultimate strength before cold work = 440 MPa

ultimate strength after cold work = 550 MPa

Explanation:

given data

AISI 1018 steel

cold work factor W = 20% = 0.20

to find out

yield strength and ultimate strength before and after the cold-work operation

solution

we know the properties of AISI 1018 steel is

yield strength σy =  370 MPa

ultimate tensile strength σu = 440 MPa

strength coefficient K = 600 MPa

strain hardness n = 0.21

so true strain is here ∈ = ln\frac{1}{1-0.2} = 0.223

so

yield strength after cold is

yield strength = K \varepsilon ^n

yield strength =  600*0.223^{0.21)

yield strength after cold work = 437.87 MPa

and

ultimate strength after cold work is

ultimate strength = \frac{\sigma u}{1-W}

ultimate strength = \frac{440}{1-0.2}

ultimate strength after cold work = 550 MPa

8 0
3 years ago
(Signal Property) Under what condition is a discrete-time signal x[????] or a continuous-time signal x(????) periodic? Determine
Cloud [144]

Answer:

a. 2x/3

b. 8

Explanation:

fundamental period can be defined to mean that at after every period of 2π radians or 360° the value of graph is repeated. For such functions the fundamental period is the period after which they repeat themselves.

It van also be looked as The fundamental period of cos(θ) is 2π. That is (for example) cos(0) to cos(2π) represents one full period.

Please see attachment for the step by step solution.

7 0
3 years ago
Define Plastic vs elastic deformation.
Snowcat [4.5K]

Answer:

Plastic deformation, irreversible or permanent. Deformation mode in which the material does not return to its original shape after removing the applied load. This happens because, in plastic deformation, the material undergoes irreversible thermodynamic changes by acquiring greater elastic potential energy.

Elastic deformation, reversible or non-permanent. the body regains its original shape by removing the force that causes the deformation. In this type of deformation, the solid, by varying its tension state and increasing its internal energy in the form of elastic potential energy, only goes through reversible thermodynamic changes.

3 0
3 years ago
14. The maximum amount a homeowner should spend on housing is
Simora [160]

Answer:

28%

Explanation:

Although there are sources that says 30% of gross income can be spent on housing, the most reliable amount that can be spent (according to other sources) is 28%.

Take for instance, you earn $5000 monthly, the maximum that you can spend on housing is:

Max = 28\% * \$5000

Using a calculator, we have:

Max = \$1400

<em>The maximum that can be spent on a monthly gross income of $5000 is $1400</em>

8 0
2 years ago
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