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3 years ago

Which group number below represents the Oxygen Group?

Physics

1 answer:

worty [1.4K]3 years ago

8 0

Oxygen has an atomic number 8, because it has 8 protons and 8 electrons.

The first shell of an atom can hold up to 2 electrons but oxygen has 8 electrons, in that eight electrons 2 are in the first shell, so it has 6 more electrons left. The second shell can hold up to 8 electrons, oxygen has only 6 more electrons after the first shell is full, so it will have 6 electrons in the second shell

From this we know that oxygen has 2 shells so it is in period 2, and by counting from left to right, the sixth box in period 2 lies on group 16

Therefore Oxygen lies on group 16 and period 2

Happy to help :)

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If a wave has a frequency of 50 Hz and a wavelength of 2 meters.<br> Find its speed.

natka813 [3]

Answer:

100 m/s

Explanation:

here we use the wave equation which states that the velocity is equal to the product of the frequency and the wavelength.

so v = 50 × 2

v = 100 m/s

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3 years ago

The part of the shore that represents the water's edge and migrates back and forth with the tide is known as the ________.

Dennis_Churaev [7]

Answer :It is know as the shore line

Explanation:

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3 years ago

A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat

Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

$s=ut-\dfrac{1}{2}at^2$

Put the value into the formula

$1200=92t+\dfrac{1}{2}\times4t^2$

$2t^2+92-1200=0$

$t=10\ sec$

We need to calculate the velocity

Using equation of motion

$v=u+at$

Put the value into the formula

$v=92+4\times10$

$v=132\ m/s$

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

$h'=h+ut-\dfrac{1}{2}at^2$

Put the value into the formula

$0=1200+132t-\dfrac{1}{2}\times9.8t^2$

$4.9t^2-132t-1200=0$

$t=34\ sec$

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

$t'=34+10$

$t'=44\ sec$

Hence, The rocket above the ground is in 44 sec.

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4 years ago

Which of the following can easily be studied objectively? history meteorology sociology theology

Vilka [71]

<h2>Answer: meteorology </h2>

Explanation:

From the given options , meteorology is the only one that can be studied objectively, since it is an interdisciplinary science that relies on basic sciences such as physics and mathematics and applied sciences to the study of the atmosphere, the weather, the phenomena produced and the physical laws that govern it. In addition, meteorology uses objective techniques to study and predict the various phenomena that occur in the atmosphere.

Unlike history, sociology and theology, in which there is a possibility of the existence of some data are subjective and not true or only based on opinions <u>without scientific evidence</u>.

8 0

3 years ago

During takeoff, an airplane goes from 0 to 60 m/s in 10 s.

Elis [28]

Answer:

see below

Explanation:

acceleration = Δv /Δt

for this situation 60 / 10 = 6 m/s^2

B) vf = vo + at

vf = 0 + 6(3) =<u> 18 m/s after 3 seconds </u>

<u />

C) vf = at

60 = 6 ( t) t = 10 seconds ( actually, this was given)

d = 1/2 a t^2

= 1/2 (6) (10)^2 = <u>300 m </u>

<u />

8 0

1 year ago