Today: fusion<span> power. </span>Fusion energy<span>, simply, is the exact opposite of fission </span>energy<span>, which comes from splitting an atom and is widely </span>used<span> to power </span>nuclear<span> plants and weapons. </span>Fusion<span> occurs constantly on our sun, which produces most of its </span>energy <span>via the </span>nuclear fusion<span> of hydrogen into helium.
Hope this helps! =)</span>
Based on the given description above, the one that it refers is GALAXY. A galaxy is a system or collection that forms clusters of millions of stars, planets, gas, dust which are held together via gravitational force. One common example of galaxy is the Milky Way Galaxy. Hope this helps.
Answer:C
Explanation: This is because the time for the 26 gram ball was around 6 seconds longer which if they were dropped at the same height then the ball with more mass would fall faster because of its gravitational pull.
Answer:
6.48 m/s
Explanation:
We are given that
Mass,M=2 kg
Radius,R=0.25 m
Height,h=3 m
Moment of inertia of solid sphere=![I=\frac{2}{5}MR^2](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B2%7D%7B5%7DMR%5E2)
We have to find the linear speed.
![\omega=\frac{v}{R}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7Bv%7D%7BR%7D)
By law of conservation of energy
![mgh=\frac{1}{2}I\omega^2+\frac{1}{2}mv^2](https://tex.z-dn.net/?f=mgh%3D%5Cfrac%7B1%7D%7B2%7DI%5Comega%5E2%2B%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![mgh=\frac{1}{2}I(\frac{v}{R})^2+\frac{1}{2}mv^2=\frac{1}{2}v^2(\frac{I}{R^2}+m)](https://tex.z-dn.net/?f=mgh%3D%5Cfrac%7B1%7D%7B2%7DI%28%5Cfrac%7Bv%7D%7BR%7D%29%5E2%2B%5Cfrac%7B1%7D%7B2%7Dmv%5E2%3D%5Cfrac%7B1%7D%7B2%7Dv%5E2%28%5Cfrac%7BI%7D%7BR%5E2%7D%2Bm%29)
Where ![g=9.8m/s^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fs%5E2)
Substitute the values
![2\times 9.8\times 3=\frac{1}{2}(\frac{2}{5R^2}MR^2+M)=\frac{7}{10}Mv^2=\frac{7}{10}(2)v^2](https://tex.z-dn.net/?f=2%5Ctimes%209.8%5Ctimes%203%3D%5Cfrac%7B1%7D%7B2%7D%28%5Cfrac%7B2%7D%7B5R%5E2%7DMR%5E2%2BM%29%3D%5Cfrac%7B7%7D%7B10%7DMv%5E2%3D%5Cfrac%7B7%7D%7B10%7D%282%29v%5E2)
![v^2=\frac{2\times 9.8\times 3\times 10}{7\times 2}](https://tex.z-dn.net/?f=v%5E2%3D%5Cfrac%7B2%5Ctimes%209.8%5Ctimes%203%5Ctimes%2010%7D%7B7%5Ctimes%202%7D)
![v=\sqrt{\frac{2\times 9.8\times 3\times 5}{7}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2%5Ctimes%209.8%5Ctimes%203%5Ctimes%205%7D%7B7%7D%7D)
![v=6.48m/s](https://tex.z-dn.net/?f=v%3D6.48m%2Fs)
Answer:
![t = 70.13 hours](https://tex.z-dn.net/?f=t%20%3D%2070.13%20hours)
Explanation:
As we know that 1 lb fat can be used to expend 4.1 k Calorie of energy
so here we know that we have to use 7.56 lb of body fat
so here the total energy that is to be utilized is given as
![Q = (4.1 \times 10^3)(7.56)](https://tex.z-dn.net/?f=Q%20%3D%20%284.1%20%5Ctimes%2010%5E3%29%287.56%29%20)
so we will have
![Q = 30996 Calorie](https://tex.z-dn.net/?f=Q%20%3D%2030996%20Calorie)
now we know that runner expends the energy at rate of 1850 kJ/h
so we have
![E = 1850 \times 10^3 kJ/h](https://tex.z-dn.net/?f=E%20%3D%201850%20%5Ctimes%2010%5E3%20kJ%2Fh)
so it is
![E = 0.44 \times 10^3 calorie/h](https://tex.z-dn.net/?f=E%20%3D%200.44%20%5Ctimes%2010%5E3%20calorie%2Fh)
now we know that time to burn this energy is given as
![t = \frac{Q}{E}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7BQ%7D%7BE%7D)
![t = \frac{30996}{0.44 \times 10^3}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B30996%7D%7B0.44%20%5Ctimes%2010%5E3%7D)
![t = 70.13 hours](https://tex.z-dn.net/?f=t%20%3D%2070.13%20hours)