<span>B. lithosphere is divided into plates.
</span>According to the theory of plate tectonics, the lithosphere is divided into plates. <span><span>
NOT:
</span>A. asthenosphere is divided into plates.
</span><span>C. asthenosphere moves over the lithosphere.
D. asthenosphere is strong and rigid.</span><span>
</span>
To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.
From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:
![\frac{V_s}{V_p} = \frac{N_s}{N_p}](https://tex.z-dn.net/?f=%5Cfrac%7BV_s%7D%7BV_p%7D%20%3D%20%5Cfrac%7BN_s%7D%7BN_p%7D)
Where
input voltage on the primary coil.
input voltage on the secondary coil.
number of turns of wire on the primary coil.
number of turns of wire on the secondary coil.
Replacing our values we have:
![V_p = 128V](https://tex.z-dn.net/?f=V_p%20%3D%20128V)
![N_p = 106](https://tex.z-dn.net/?f=N_p%20%3D%20106)
![N_s = 340](https://tex.z-dn.net/?f=N_s%20%3D%20340)
Replacing,
![\frac{V_s}{128} = \frac{340}{106}](https://tex.z-dn.net/?f=%5Cfrac%7BV_s%7D%7B128%7D%20%3D%20%5Cfrac%7B340%7D%7B106%7D)
![V_s = 410.56V](https://tex.z-dn.net/?f=V_s%20%3D%20410.56V)
From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:
![V_s I_s = V_p I_p](https://tex.z-dn.net/?f=V_s%20I_s%20%3D%20V_p%20I_p)
Where
= Current Primary Coil
= Current secundary Coil
Therefore:
![I_s = \frac{V_p I_p}{V_s}](https://tex.z-dn.net/?f=I_s%20%3D%20%5Cfrac%7BV_p%20I_p%7D%7BV_s%7D)
![I_s = \frac{(128)(6)}{410.56}](https://tex.z-dn.net/?f=I_s%20%3D%20%5Cfrac%7B%28128%29%286%29%7D%7B410.56%7D)
![I_s = 1.87 A](https://tex.z-dn.net/?f=I_s%20%3D%201.87%20A)
Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A
Answer:
h = R/4 = 1.5925 x 10⁶ m = 1592.5 km
Explanation:
The variation in the value of acceleration due to gravity value with respect to the altitude is given by the following general formula:
![g' = g(1-2\frac{h}{R})](https://tex.z-dn.net/?f=g%27%20%3D%20g%281-2%5Cfrac%7Bh%7D%7BR%7D%29)
where,
h = altitude from surface of earth = ?
g = acceleration due to gravity on surface of earth = 9.81 m/s²
R = Radius of Earth = 6.37 x 10⁶ m
g' = acceleration due to gravity at given altitude = g/2
Therefore,
![\frac{g}{2} = g(1-2\frac{h}{R})\\\\2\frac{h}{R} = 1-\frac{1}{2}\\\\2\frac{h}{R} = \frac{1}{2}\\\\\frac{h}{R} = \frac{1}{4}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7B2%7D%20%20%3D%20g%281-2%5Cfrac%7Bh%7D%7BR%7D%29%5C%5C%5C%5C2%5Cfrac%7Bh%7D%7BR%7D%20%3D%201-%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C2%5Cfrac%7Bh%7D%7BR%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cfrac%7Bh%7D%7BR%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C)
<u>h = R/4 = 1.5925 x 10⁶ m = 1592.5 km</u>