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2 years ago

5

A 4kg object is moving at a speed of 5 m/sec.how much kinetic energy does the objects have

1 answer:

Marat540 [252]2 years ago

7 0

Answer:

It has a grand total of 5

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A robot is on the surface of Mars. The angle of depression from a camera in the robot to a rock on the surface of Mars is 13.69

ra1l [238]

Answer:

The distance between the camera and the rock is 836.6 cm

Explanation:

A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:

cos α = adjacent/hypotenuse

cos(76.31) = 198.0/h

h = 198.0/cos(76.31)

h = 836.6 cm

3 0

3 years ago

WILL GIVE BRAINLIEST!!<br> What is a way to transfer charge in which an object becomes polarized?

Andreyy89

Answer:

I answered Number 4 (Solids and Elasticity)

Explanation:

solids and elasticity

4 0

2 years ago

A particle with charge 3.01 µC on the negative x axis and a second particle with charge 6.02 µC on the positive x axis are each

ra1l [238]

Answer:

The third particle should be at 0.0743 m from the origin on the negative x-axis.

Explanation:

Let's assume that the third charge is on the negative x-axis. So we have:

$E_{1}+E_{3}-E_{2}=0$

We know that the electric field is:

$E=k\frac{q}{r^{2}}$

Where:

k is the Coulomb constant
q is the charge
r is the distance from the charge to the point

So, we have:

$k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0$

Let's solve it for r(3).

$\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0$

$r_{3}=0.0743\:$

Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.

I hope it helps you!

3 0

2 years ago

If the velocity of the particle is uniform, then the path of the particle must be a

lianna [129]

Answer:

write yoir question carefully i am not understanding it

6 0

3 years ago

An object with a mass of 2.0 kg accelerates 2.0 m/s2 when an unknown force is applied to it. What is the amount of the force?

MAXImum [283]

force is mass * acceleration

so 2kg * 2m/s^2 = 4 N

5 0

3 years ago