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3 years ago

Which plant is considered an invasive species in Shenandoah National Park in Virginia?

Chemistry

1 answer:

Tema [17]3 years ago

4 0

Answer:

B) The tree-of-heaven is originally from China. It produces a chemical that prevents other plants from growing around it.

Explanation:

In ecology, a plant is said to be "INVASIVE" if it is FOREIGN or NON-NON-NATIVE to a particular region or area and also poses a great threat to the native species of that region. An invasive species, when introduced into a foreign habitat, heavily competes with the existing local species of that same habitat.

This is the case of the tree-of-heaven, which is originally from China. The tree produces a chemical that prevents other plants from growing around it. Note that this plant species is foreign to the Shenandoah National Park in Virginia as it originates from China. Likewise it harms the local or native species of the park by secreting a chemical that prevents other plants from growing around it. This characteristics portrays a plant that is INVASIVE.

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8)__MgCl2 +<br> Li2CO3 →<br> _MgCO3 +<br> LiCl Reaction Type:_<br> TT

Studentka2010 [4]

Reaction type : Double-Replacement reactions

<h3>Further explanation</h3>

Given

Reaction

MgCl2 + Li2CO3 → MgCO3 + LiCl

Required

Balanced equation

Reaction type

Solution

Balanced equation

Li2CO3 (s) + MgCl2 (aq) → MgCO3 (s) + 2 LiCl (aq)

Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

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3 years ago

Which chemical reaction shows photosynthesis?

Komok [63]

Answer:

Explanation:

Photosynthesis is reverse combustion, thus, water and carbon dioxide should be reactants. Photosynthesis also needs sunlight, so A it is.

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3 years ago

A piece of copper (12.0 g) is heated to 100.0 °C. A piece of chromium (also 12.0 g) is chilled in an ice bath to 0 °C. The speci

Gennadij [26K]

Answer:

(a) Slightly greater than 20.0 °C

(b) $T_F=293.46K=20.3^oC$

Explanation:

Hello,

In this case, since we are talking about the equilibrium temperature that will be reached when the copper, chromium and water samples get in contact, the following equation is useful to describe such situation:

$\Delta H_{water}+\Delta H_{copper}+\Delta H_{chromium}=0\\$

Thus, in terms of masses, heat capacities and temperatures we consider the final temperature as the unknown:

$m_{water}Cp_{water}(T_F-T_{water})+m_{copper}Cp_{copper}(T_F-T_{copper})+m_{chromium}Cp_{chromium}(T_F-T_{chromium})=0$ In such a way, by knowing that the heat capacities of copper and chromium are 0.386 and 0.45 J/(g°C) respectively, by solving for the equilibrium temperature one has:

$T_F=\frac{m_{water}Cp_{water}T_{water}+m_{Cu}Cp_{Cu}T_{Cu}+m_{Cr}Cp_{Cr}T_{Cr}}{m_{water}Cp_{water}+m_{Cu}Cp_{Cu}+m_{Cr}Cp_{Cr}}$

$T_F=\frac{200.0g*4.184\frac{J}{g*K}* 293.15K+12.0g*0.386\frac{J}{g*K} *373.15K+12.0g*0.45\frac{J}{g*K}*273.15K}{200.0g*4.184\frac{J}{g*K}+12.0g*0.386\frac{J}{g*K} +12.0g*0.45\frac{J}{g*K}}\\\\T_F=293.46K=20.3^oC$

Hence, the resulting temperature of water turns out slightly greater than 20.0 °C.

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Alisiya [41]

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