Answer:
No bro that bro had it coming he should have known when to stop
Explanation:
Answer:
The correct option is;
B) 179 g
Explanation:
The parameters given are;
Mass of H₂ that takes part in the reaction = 2.23 g
Molar mass of hydrogen gas, H₂ = 2.016 g
Number of moles, n, of hydrogen gas H₂ is given by the relation;

Chemical equation for the reaction;
H₂ + Br₂ → 2HBr
Given that one mole of H₂ reacts with one mole of Br₂ to produce two moles of HBr
1.106 mole of H₂ will react with 1.106 mole of Br₂ to produce 2 × 1.106 which is 2.212 moles of HBr
The molar mass, of HBr = 80.91 g/mol
The mass of HBr produced = Molar mass of HBr × Number of moles of HBr
The mass of HBr produced = 80.91 × 2.212 = 178.997 g ≈ 179 grams
Therefore, the correct option is B) 179 g.
Answer:

Explanation:
Assume the reaction is the combustion of propane.
Word equation: propane plus oxygen produces carbon dioxide and water
Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)
Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)
(a) Table of enthalpies of formation of reactants and products

(b)Total enthalpies of reactants and products

ΔᵣH° is negative, so the reaction is exothermic.
<span>True. In chemistry, mixtures are two (or more) substances mixed together but not combined chemically. This means there are no chemical bonds that have formed between the substances. As such, they can be separated with physical processes.</span>