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3 years ago

In which of the following situations would a spring scale be used?

1 answer:

6 0

Main uses of spring balances are industrial, especially related to weighing heavy loads such as trucks, storage silos, and material carried on a conveyor belt. They are also common in science education as basic accelerators. They are used when the accuracy afforded by other types of scales can be sacrificed for simplicity, cheapness, and robustness.

A spring balance measures the weight of an object by opposing the force of gravity acting with the force of an extended spring. hope you can get some use from this

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Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How hig

barxatty [35]

Answer:30.61m

Explanation: None sorry i took the test and this is what i got..We may be taking different test idk...

4 0

3 years ago

If the mass of a moving object decreases from 100 grams to 25 grams, what happens to its momentum

cluponka [151]

The momentum will become 1/4 as much.
0.100 v === 0.25 v

5 0

3 years ago

In a Broadway performance, an 83.0-kg actor swings from a R = 3.90-m-long cable that is horizontal when he starts. At the bottom

Veseljchak [2.6K]

Answer:

$h = 2.821\,m$

Explanation:

The speed of the actor before the collision is found by means of the Principle of Energy Conservation:

$(83\,kg)\cdot(9.807\,\frac{m}{s})\cdot (3.90\,m) = \frac{1}{2}\cdot (83\,kg)\cdot v^{2}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (3.90\,m)}$

$v \approx 8.746\,\frac{m}{s}$

The speed after the inelastic collision is obtained by using the Principle of Momentum Conservation:

$(83\,kg)\cdot (8.746\,\frac{m}{s} )+(55\,kg)\cdot (0\,\frac{m}{s} ) = (83\,kg + 55\,kg)\cdot v$

$v = 5.260\,\frac{m}{s}$

Lastly, the maximum height is determined by using the Principle of Energy Conservation again:

$\frac{1}{2}\cdot (138\,kg)\cdot (5.260\,\frac{m}{s} )^{2} = (138\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot h$

$h = \frac{(5.260\,\frac{m}{s} )^{2}}{9.807\,\frac{m}{s^{2}} }$

$h = 2.821\,m$

8 0

3 years ago

Which image represents the force on a positively charged particle caused by an approaching magnet?

Amanda [17]

Answer:

Image B represents the force on a positively charged particle caused by an approaching magnet.

Explanation:

The most fundamental law of magnetism is that like shafts repulse each other and dissimilar to posts pull in one another; this can without much of a stretch be seen by endeavoring to put like posts of two magnets together. Further attractive impacts additionally exist. On the off chance that a bar magnet is cut into two pieces, the pieces become singular magnets with inverse shafts. Also, pounding, warming or winding of the magnets can demagnetize them, on the grounds that such dealing with separates the direct game plan of the particles. A last law of magnetism alludes to maintenance; a long bar magnet will hold its magnetism longer than a short bar magnet. The domain theory of magnetism expresses that every single enormous magnet involve littler attractive districts, or domains. The attractive character of domains originates from the nearness of significantly littler units, called dipoles. Iotas are masterminded in such a manner in many materials that the attractive direction of one electron counteracts the direction of another; in any case, ferromagnetic substances, for example, iron are unique. The nuclear cosmetics of these substances is with the end goal that littler gatherings of particles unite as one into zones called domains; in these, all the electrons have the equivalent attractive direction.

4 0

2 years ago

A football player at practice pushes a 60 kg blocking sled across the field at a constant speed. The coefficient of kinetic fric

vichka [17]

Answer:

The force must he apply to the sled is of F= 764.4 N.

Explanation:

m= 60 kg

g= 9.8 m/s²

μ=0.3

W= m*g

W= 588 N

Fr= μ*W

Fr= 176.4 N

F= W + Fr

F= 764.4 N

4 0

3 years ago

Read 2 more answers