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34kurt
3 years ago
14

How many significant digits are in the measurement 4,032,010 m/s?

Physics
2 answers:
choli [55]3 years ago
5 0
Since there is no decimal point in the number given above, the counting for the number of the significant figures will start from the left. Then, the first zero from the left is insignificant. Therefore, in this number there are 6 significant figures. 
3241004551 [841]3 years ago
4 0

Answer:

6

Explanation:

The rules which we have to use to find the number of significant figures here are given below:

1. If a number does not contain a decimal point, then the zeros between two non zero digits are significant.

2. the trailing zeros are not significant.

The number is

4,032, 010 m/s

so, the zero between 4 and 3 is significant

the zero between 2 and 1 is significant

the zero at the last is not significant

So, the number of significant figures are 6.

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What is a wavelength?
Pavel [41]

A wavelength is the distance between two identical peaks, troughs or crests in a wave. The unit of wavelength can be meters, centimeters, millimeters, nanometers and so on. 

6 0
3 years ago
Show that the acceleration of any object down an incline where friction behaves simply (that is, where fk=μkN ) is a=g(sinθ−μkco
11Alexandr11 [23.1K]

Answer:

a=g(sinθ-μkcosθ)

Explanation:

In an inclined plane the forces that interact with the object can be seen in the figure. The normal force, the weight w and the decomposition of the force vector of weight can be observed.

wx=m*g*sinθ

wy=m*g*cosθ

As the objects moves down an incline, acceleration in y axis is 0.

Then, by second Newton's Law:

Fy = m*ay

FN - m*g cos θ = 0,

FN=m*g cos θ

In x axis the forces that interacs are the x component of weight and friction force:

Fx = m*ax

mg sen u-FN*μk=m*a

Being friction force, Fr=FN*μk, we replace with its value in below formula:

m*g *sinθ-(m*g*cosθ*μk)=m*a

Then, isolating a:

a=(m*g sinθ-(m*g*cosθ*μk))/m

Solving, we have next equation:

a=g sinθ-(g*cosθ*μk)

Applying distributive property we have:

a=g*(sinθ-μk*cosθ)

5 0
3 years ago
A 3.8kw elective motor powers an inclined conveyer belt. It is designed to lift heavy boxes from the warehouse floor to loading
zhannawk [14.2K]

Answer:

See the answers below

Explanation:

To solve this problem we must use the definition of power and work in physics.

a)

The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.

Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.

b)

Power is defined as the relationship of work over time. Therefore we have:

P=W/t

where:

P = power = 3.8 [kW] = 3800 [W]

W = work [J]

t = time = 14 [s]

W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ]

c)

Since the given time is equal to the given time at Point b, we can use the same work calculated.

We know that work is defined as the product of force by the distance traveled.

W =F*d

So, the force is equal to:

F=W/d\\F=53200/5.3\\F=10037.73[N]

Now we know that force is defined as the product of mass by gravitation acceleration.

F =m*g

where:

F = force or weight = 10037.73 [N]

g = gravity acceleration = 9.81 [m/s²]

m = mass [kg]

m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg]

d)

This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.

E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}

where:

h = elevation = 4.7 [m]

v = velocity [m/s]

m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} }   \\v = 9.6 [m/s]

7 0
3 years ago
A radio station's channel, such as 100.7 fm or 92.3 fm, is actually its frequency in megahertz (mhz), where 1mhz=106 hz and 1hz=
AURORKA [14]
The frequency of the radio station is
f=88.7 fm= 88.7 MHz = 88.7 \cdot 10^6 Hz

For radio waves (which are electromagnetic waves), the relationship between frequency f and wavelength \lambda is
\lambda= \frac{c}{f}
where c is the speed of light. Substituting the frequency of the radio station, we find the wavelength:
\lambda= \frac{3 \cdot 10^8 m/s}{88.7 \cdot 10^6 Hz}=3.38 m
6 0
4 years ago
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tangare [24]

Explanation:

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