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Phantasy [73]
3 years ago
15

An oxygen atom that gains 2 electrons becomes

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
3 0

Answer:

When an oxygen atom gains 2 electrons, it becomes O2−, as it has 2 extra electrons. This causes it to become a negatively-charged ion or an anion. When it bonds with other elements, it can be considered an oxide.

Explanation:

I am Lyosha [343]3 years ago
3 0

Answer:

When an oxygen atom gains 2 electrons, it becomes O2− , as it has 2 extra electrons. This causes it to become a negatively-charged ion, or an anion. When it bonds with other elements, it can be considered an oxide.F

Explanation:

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Mrs. Stark weighs 70kg. How much Potential Energy does she have if she stands on the roof of an 80m tall building?
8_murik_8 [283]
E = mgh

E = 70*9.81*80

E = 54936 J
5 0
4 years ago
PH que tendra una solución cuya concentracion de [OH-] = 1x10-4
natta225 [31]
I don’t understand wha u just said but thanks for the points
7 0
3 years ago
In pure water at 25 °C, the concentration of a saturated solution of CuF2 is 7.4 × 10−3 M. If measured at the same temperature,
Romashka-Z-Leto [24]

Answer:

The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is  4.0×10⁻⁵ M.

Explanation:

Consider the ICE take for the solubility of the solid, CuF₂ as:

                                  CuF₂    ⇄     Cu²⁺ +    2F⁻

At t=0                            x                 -              -

At t =equilibrium      (x-s)                s           2s          

The expression for Solubility product for CuF₂ is:

K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2

K_{sp}=s\times {2s}^2

K_{sp}=4s^3

Given  s = 7.4×10⁻³ M

So, Ksp is:

K_{sp}=4\times (7.4\times 10^{-3})^3

K_{sp}=4\times (7.4\times 10^{-3})^3

Ksp = 1.6209×10⁻⁶

Now, we have to calculate the solubility of CuF₂ in NaF.

Thus, NaF already contain 0.20 M F⁻ ions

Consider the ICE take for the solubility of the solid, CuF₂ in NaFas:

                                  CuF₂    ⇄     Cu²⁺ +    2F⁻

At t=0                            x                 -            0.20

At t =equilibrium      (x-s')             s'         0.20+2s'         

The expression for Solubility product for CuF₂ is:

K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2

1.6209\times 10^{-6}={s}'\times ({0.20+2{s}'})^2

Solving for s', we get

<u>s' = 4.0×10⁻⁵ M</u>

<u>The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is  4.0×10⁻⁵ M.</u>

3 0
4 years ago
(NEED ANSWER NOW)
Anna11 [10]

Answer:it’s C

Explanation:

A distant luminous object travels rapidly away from an observer.

4 0
3 years ago
By definition 12 grams of carbon-12 must contain how many atoms?
krek1111 [17]
It is defined as the amount of a substance that contains as many particles as there are atoms in 12 grams of pure carbon-12. So, 1 molecule contains 6.022×10^23 elementary entities of the substance.

Hope that helps
5 0
4 years ago
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