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ziro4ka [17]
3 years ago
9

If 15 L of chlorine reacts at a constant temperature of 298 K and pressure of 9 atm, how many grams of hydrochloric acid (HCl) a

re produced?
Chemistry
1 answer:
stepan [7]3 years ago
7 0

Answer:400k

Explanation:

You might be interested in
How many mL of a stock solution of 2.00 M KNO3 are needed to prepare 100.0 mL of 0.15M KNO3? with work plz
Tatiana [17]
Using the law of dilution :

Mi x Vi =  Mf x Vf

2.00 x Vi = 0.15 x 100.0

2.00 x Vi = 15

Vi = 15 / 2.00

Vi = 7.5 mL

hope this helps!


3 0
3 years ago
3. How many moles of silver is 8.46x1024 atoms of<br> silver?
ioda

Answer:

<h2>14.05 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.46 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 14.053156

We have the final answer as

<h3>14.05 moles</h3>

Hope this helps you

6 0
2 years ago
Question 1:
Alona [7]

Question 1:

(a) Sulfurous acid: H2SO3

Sulfuric acid: H2SO4

(b) Nitrous acid: H2NO2

Nitric acid: H2NO3

Question 2:

To calculate the pH, based on concentration of H+ ions, there is one formula:

ph =   - log_{10}(c(h + ))

So the pH of this solution is

-  log_{10}( {10}^{ - 9} )  = 9

(the solution is basic).

5 0
3 years ago
Find the new pressure of 5 L of a gas at STP that is cooled to 250 K and expanded to 6L
UNO [17]
I’m so sorry i have to do this 5L 24
5 0
3 years ago
500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.
jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL

Putting values in above equation, we get:

0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M

Hence, the concentration of diluted solution is 0.16 M

5 0
3 years ago
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