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mel-nik [20]
3 years ago
13

The influence of likes and dislikes on thinking called?

Physics
1 answer:
jenyasd209 [6]3 years ago
3 0
'A biased oppinion'
 When you like something and right a report on it your opinion will come through about that subject, the same thing occurs if you dislike something. 
:) Hope this helps x
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The current world-record motorcycle jump is 77.0 m, set by Jason Renie. Assume that he left the take-off ramp at 13.0° to the ho
kotegsom [21]

Answer:

The take-off speed is 41.48 \frac{m}{s}

Explanation:

Given :

Range R = 77 m

Projectile angle \alpha  = 13°

From the formula of range,

  R = \frac{v_{o} ^{2}   }{g} \sin 2\alpha

Find the velocity from above equation,

  v_{o} = \sqrt{\frac{gR}{\sin 2 \alpha } }

  v_{o} = \sqrt{\frac{9.8 \times 77}{\sin 26} }                              ( ∵ g = 9.8 \frac{m}{s^{2} } )

  v_{o} = 41.48 \frac{m}{s}

Therefore, the take-off speed is 41.48 \frac{m}{s}

7 0
3 years ago
I pooped in the bathtub? I tryed to poop in my hand so i can carry it to the fish tank so they can feed thereselfs but it fell t
cupoosta [38]

Answer:

Sorry don't know

Explanation:

Ask google

8 0
2 years ago
Looking that following diagram of bar magnets, determine if the magnets will or will not connect (attract) and why.
vovangra [49]

Answer: They will NOT connect because like poles are facing each other, and like poles repel each other.

3 0
3 years ago
Question 15: At the edge of a lake you throw a stone with a velocity of 29 m/s at an angle of 45°. The stone is in the air for 4
Marianna [84]
Get your numbers gathered up and solve the problem in the ordered step
8 0
3 years ago
A cubical block of wood, 10.0 cm on a side, floats at the interface between oil and water with its lower surface 1.50 cm below t
bezimeni [28]

Answer:

the gauge pressure at the upper face of the block is 116 Pa

Explanation:

Given the data in the question;

A cubical block of wood, 10.0 cm on a side.

height h = 1.50 cm = ( 1.50 × ( 1 / 100 ) ) m = 0.0150 m

density ρ = 790 kg/m³

Using expression for the gauged pressure;

p-p₀ = ρgh

where, p₀ is atmospheric pressure, ρ is the density of the substance, g is acceleration due to gravity and h is the depth of the fluid.

we know that, acceleration due to gravity g = 9.8 m/s²

so we substitute

p-p₀ = 790 kg/m³gh × 9.8 m/s² × 0.0150 m

= 116.13 ≈ 116 Pa

Therefore, the gauge pressure at the upper face of the block is 116 Pa

4 0
3 years ago
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