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blagie [28]
3 years ago
14

Two engineers are to solve an actual heat transfer problem in a manufacturing facility. Engineer A makes the necessary simplifyi

ng assumptions and solves the problem analytically, while engineer B solves it numerically using a powerful software package. Engineer A claims he solved the problem exactly and, thus, his results are better, while engineer B claims that he used a more realistic model and, thus, his results are better. Will the experiments prove engineer B right
Engineering
1 answer:
deff fn [24]3 years ago
5 0

Answer:

Engineer A results will be more accurate

Explanation:

Analytical method is better than numerical method. Engineer A has used analytical method and therefore his results will be more accurate because he used simplified method. Engineer B has used software to solve the problem related to heat transfer his results will be approximate.

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Explanation:

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A pin-supported structure has unrestrained rotations at the support locations.a) True b) False
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Read 2 more answers
A solid cylinder is concentric with a straight pipe. The cylinder is 0.5 m long and has an outside diameter of 8 cm. The pipe ha
poizon [28]

Answer :  

The force needed to move the cylinder is 25.6 N

<h2>Further explanation  </h2>

Given that,  

Length of the cylinder, l = 0.5 m  

Outer diameter of the cylinder, d = 8 cm = 0.08 m  

Outer radius of the cylinder, r=0.04\ m  

Inside diameter of the pipe, d = 8.5 cm = 0.085 m  

Inside radius of the pipe, r=0.0425\ m  

Specific gravity of the oil, \rho=0.92  

Density of oil, d=\rho\times \rho_w

Kinematic viscosity of the oil, v=5.57\times 10^{-4}\ m^2/s  

Velocity of the cylinder, u = 1 m/s  

We need to find the force needed to move the cylinder. Let the force is F.  

Specific gravity is defined as the ratio of the density of the substance to the density of water.  

Kinematic viscosity is the acquired resistance of a fluid when there is no external force is acting except gravity. It is denoted by v.

Absolute viscosity is given by :

v=\dfrac{\mu}{d}

Where, d = density of oil

And d=\rho\times \rho_w (density of oil = specific gravity × density of water )

d=0.92\times 10^3\ kg/m^3

So,  

\mu=v\times d..............(1)

\mu=5.57\times 10^{-4}\ m^2/s\times 0.92\times 10^3\ kg/m^3

\mu=0.512\ Pa-s

The separation between the cylinder and pipe is given by :

dy=\dfrac{d_p-d_c}{2}=\dfrac{8.5-8}{2}=0.25\ cm=0.0025\ m

d_p\ and\ d_c are diameter of pipe and cylinder respectively.  

The mathematical expression for the Newton's law of viscosity can be written as:  

\tau\propto\dfrac{du}{dy}  

\tau=\mu\times \dfrac{du}{dy}..........(2)  

Where  

\tau = Shear stress, \tau=\dfrac{F}{A}............(3)  

\mu = viscosity  

\dfrac{du}{dy} = rate of shear deformation

On rearranging equation (1), (2) and (3) we get :  

\dfrac{F}{A}=v\times \rho\times \dfrac{du}{dy}...............(4)  

A is the area of the cylinder, A=2\pi rl  

Equation (4) becomes :  

F=v\times \rho\times \dfrac{du}{dy}\times 2\pi rl..............(5)

A=\pi d\times l

A=\pi \times 0.08\ m\times 0.5\ m

A=0.125\ m^2

Now, equation (5) becomes :

F=(v\times \rho)\times \dfrac{du}{dy}\times 2\pi rl

F=(0.512\ Pa-s)\times (\dfrac{1}{0.0025\ m})\times \times 0.125\ m^2

F = 25.6 N

<h2>Learn more  </h2>

Kinematic viscosity : brainly.com/question/12947932

<h2>Keyword :  </h2>

Specific gravity, Kinematic viscosity, Area of cylinder, fluid mass density.  

7 0
3 years ago
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