Answer:
Gold, Platinum, Silver, Ruthenium
Answer:
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Answer:
the answer is A because when something is going straight it wont change unless its acted upon by a force
Explanation:
Answer:
- The abundance of 107Ag is 51.5%.
- The abundance of 109Ag is 48.5%.
Explanation:
The <em>average atomic mass</em> of silver can be expressed as:
107.87 = 106.90 * A1 + 108.90 * A2
Where A1 is the abundance of 107Ag and A2 of 109Ag.
Assuming those two isotopes are the only one stables, we can use the equation:
A1 + A2 = 1.0
So now we have a system of two equations with two unknowns, and what's left is algebra.
First we<u> use the second equation to express A1 in terms of A2</u>:
A1 = 1.0 - A2
We <u>replace A1 in the first equation</u>:
107.87 = 106.90 * A1 + 108.90 * A2
107.87 = 106.90 * (1.0-A2) + 108.90 * A2
107.87 = 106.90 - 106.90*A2 + 108.90*A2
107.87 = 106.90 + 2*A2
2*A2 = 0.97
A2 = 0.485
So the abundance of 109Ag is (0.485*100%) 48.5%.
We <u>use the value of A2 to calculate A1 in the second equation</u>:
A1 + A2 = 1.0
A1 + 0.485 = 1.0
A1 = 0.515
So the abundance of 107Ag is 51.5%.
Answer:
1) 1 N2 + 3 H2 2 NH3
2) 2 KClO3 2 KCl + 3 O2
3) 2 NaCl + 1 F2 2 NaF + 1 Cl2
4) 2 H2 + 1 O2 2 H2O
5) 1 Pb(OH)2 + 2 HCl 2 H2O + 1 PbCl2
6) 2 AlBr3 + 3 K2SO4 6 KBr + 1 Al2(SO4)3
7) 1 CH4 + 2 O2 1 CO2 + 2 H2O
8) 1 C3H8 + 5 O2 3 CO2 + 4 H2O
9) 2 C8H18 + 25 O2 16 CO2 + 18 H2O
10) 1 FeCl3 + 3 NaOH 1 Fe(OH)3 + 3 NaCl
11) 4 P + 5 O2 2 P2O5
12) 2 Na + 2 H2O 2 NaOH + 1 H2
13) 2 Ag2O 4 Ag + 1 O2
14) 1 S8 + 12 O2 8 SO3
15) 6 CO2 + 6 H2O 1 C6H12O6 + 6 O2
16) 1 K + 1 MgBr 1 KBr + 1 Mg
17) 2 HCl + 1 CaCO3 1 CaCl2 + 1 H2O + 1 CO2
18) 1 HNO3 + 1 NaHCO3 1 NaNO3 + 1 H2O + 1 CO2
19) 2 H2O + 1 O2 2 H2O2
20) 2 NaBr + 1 CaF2 2 NaF + 1 CaBr2
21) 1 H2SO4 + 2 NaNO2 2 HNO2 + 1 Na2SO4
(RECTANGLES ARE ARROWS)