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kari74 [83]
3 years ago
6

Which has a lower freezing point ice or ice cream?

Chemistry
2 answers:
OverLord2011 [107]3 years ago
8 0
-0° freezing point ice or ice cream
Vladimir [108]3 years ago
4 0

Ice cream will have lower freezing point than ice. this can be understood with the concept of freezing point depression, which is a colligative property. Colligative properties are those which depends upon number of solvent/ solute particles. Ex: elevation in boiling point , osmotic pressure. If we add a nonvolatile solute in a solvent, its freezing point decreases.  In case of ice cream we add sugar which lowers its freezing point, aa sugar is a non volatile solute.

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Jobisdone [24]

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How many hydrogen atoms are in 35.0 grams of hydrogen gas? How many hydrogen atoms are in 35.0 grams of hydrogen gas? 4.25 × 102
Ede4ka [16]

Answer: 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{35.0g}{2g/mol}=17.5moles

1 mole of hydrogen (H_2) = 2\times 6.023\times 10^{23}=12.05\times 10^{23} atoms

17.5 mole of hydrogen (H_2) = \frac{12.05\times 10^{23}}{1}\times 17.5=2.12\times 10^{25} atoms

There are 2.12\times 10^{25} atoms of hydrogen are there in

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8 0
3 years ago
A ________ reaction occurs when one compound reacts and is broken down into different elements or simpler compounds?
faust18 [17]

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Ede4ka [16]
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3 years ago
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What is the new concentration of a solution of CaSO3 if 10.0 mL of a 2.0 M CaSO3 solution is diluted to 100 ml?
kifflom [539]

Answer: The new concentration of a solution of CaSO_{3} is 0.2 M 10.0 mL of a 2.0 M CaSO_{3} solution is diluted to 100 mL.

Explanation:

Given: V_{1} = 10.0 mL,      M_{1} = 2.0 M

V_{2} = 100 mL,           M_{2} = ?

Formula used to calculate the new concentration is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\10.0 mL \times 2.0 M = M_{2} \times 100 mL\\M_{2} = 0.2 M

Thus, we can conclude that the new concentration of a solution of CaSO_{3} is 0.2 M 10.0 mL of a 2.0 M CaSO_{3} solution is diluted to 100 mL.

5 0
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