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Lerok [7]
3 years ago
13

Select the missing words to complete the definition of buffer capacity. Buffer capacity is the _____________ of acid or base a b

uffer can handle before pushing the _____________ outside of the buffer range.
Chemistry
1 answer:
horsena [70]3 years ago
8 0

Answer:

amount, pH value.

Explanation:

The buffer range is the pH range in which the buffer performs optimally, i.e., neutralizes even when a strong acid or base is introduced to it and resists any major change in its pH value.

The buffer capacity is the amount of acid or base that can be added before the pH of the buffer solution changes significantly.

Thus, the final statement becomes,

Buffer capacity is the amount of acid or base a buffer can handle before pushing the pH value outside of the buffer range.

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Magnesium (24.30g) reacts with hydrogen chloride (xg) to produce hydrogen gas(2.04g) and magnesium chloride (96.90g). How much h
weqwewe [10]

Answer:

Answer is 74.42 if you are on cK-12.

Explanation:

6 0
3 years ago
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What is the wavelength of a light that has a frequency of 5.00x10 to the 12 power s negative 1 power
Lilit [14]

The wavelength of the light is 6.00 × 10^(-5) m.

The formula connecting frequency <em>f</em> and wavelength λ is

<em>f</em>λ = <em>c</em>

where <em>c</em> = the speed of light [2.998 × 10^8 m·s^(-1)]

We can rearrange the formula to get

λ = <em>c</em>/<em>f </em>

∴ λ = 2.998 × 10^10 m·s^(-1)/5.00 × 10^12 s^(-1) = 6.00 × 10^(-5) m = 60.0 µm

4 0
4 years ago
A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling
Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is 4.90\times 10^{-3}mol/L

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L

Hence, the concentration of copper fluoride in the solution is 4.90\times 10^{-3}mol/L

4 0
3 years ago
How are we made of the same atoms in stars?
MariettaO [177]
Stardust atoms are heavier elements, the percentage of star mass in our body is much more impressive. Most hydrogen in our body floats around in the form of water .
3 0
3 years ago
A 0.420 M Ca(OH)2 solution was prepared by dissolving 64.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
nikitadnepr [17]

The volume of the solution is given below which can be calculated using the molarity formula as 2.18 litres.

<h3>Define the molarity of a solution.</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}

Given data:

M= 0.420M

mass = 64.0 grams

Molar Mass= 74g/mol

To find:

The volume of solution=?

The calculation for a number of moles:

n= \frac{m}{M}

n= \frac{64}{70}

n= 0.91 moles

Molarity=  \frac{n}{V}

V= \frac{0.91}{0.420}

V= 2.1768 litres

Thus, the volume of the solution is 2.18 litres.

Find more information about Molarity here:

brainly.com/question/26873446

#SPJ1

6 0
2 years ago
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