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Lerok [7]
2 years ago
13

Select the missing words to complete the definition of buffer capacity. Buffer capacity is the _____________ of acid or base a b

uffer can handle before pushing the _____________ outside of the buffer range.
Chemistry
1 answer:
horsena [70]2 years ago
8 0

Answer:

amount, pH value.

Explanation:

The buffer range is the pH range in which the buffer performs optimally, i.e., neutralizes even when a strong acid or base is introduced to it and resists any major change in its pH value.

The buffer capacity is the amount of acid or base that can be added before the pH of the buffer solution changes significantly.

Thus, the final statement becomes,

Buffer capacity is the amount of acid or base a buffer can handle before pushing the pH value outside of the buffer range.

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Fossil fuels are:
Scorpion4ik [409]

Answer:

d

Explanation:

7 0
3 years ago
How many grams of NH3 can be produced from 2.51 mil of N2 and excess H2 ?
salantis [7]

Answer:

85.34g of NH3

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

Step 2:

Determination of the number of moles of NH3 produced by the reaction of 2.51 moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 2.51 moles of N2 will react to produce = (2.51 x 2)/1 = 5.02 moles of NH3.

Therefore, 5.02 moles of NH3 is produced from the reaction.

Step 3:

Conversion of 5.02 moles of NH3 to grams. This is illustrated below:

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Number of mole of NH3 = 5.02 moles

Mass of NH3 =..?

Mass = mole x molar Mass

Mass of NH3 = 5.02 x 17

Mass of NH3 = 85.34g

Therefore, 85.34g of NH3 is produced.

3 0
3 years ago
Given a fixed amount of gas held at constant pressure, calculate the volume (in L) it would occupy if a 3.50 L sample were coole
Over [174]

Answer:

V₂ = 2.91 L

Explanation:

Given data:

Initial volume = 3.50 L

Initial temperature = 90.0°C (90+273 = 363 K)

Final temperature = 30.0 °C  ( 30 +273 = 303 K)

Final volume = ?

Solution:

V₁ = Initial volume

T₁  =  Initial temperature

V₂ = Final volume

T₂ = Final temperature

V₁/T₁  =  V₂/T₂

3.50 L / 363 K) =  V₂ / 303 K)

V₂ = 0.0096 L/K × 303 K

V₂ = 2.91 L

6 0
3 years ago
Which is the formula for calculating density
o-na [289]

The Density Calculator uses the formula p=m/V, or density (p) is equal to mass (m) divided by volume (V). The calculator can use any two of the values to calculate the third. Density is defined as mass per unit volume.

7 0
3 years ago
Need answer ASAP!! The specific heat capacity of metal A is twice that of metal B. Based on
AURORKA [14]

Answer:

last choice

Explanation:

Specific heat of a metal is    j/kg-c

It says nothing about melting point or heat of fusion

A = twice B   =  2 * j/kg-c       B = j/kg-c

 if   j is constant and mass is the same we can write this more like

    A = 2 /C       and    B = 1/C

  or    A ~  C/2      and   B~  C

now you can see that the temp change in A   will be 1/2   that of B

4 0
1 year ago
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