Answer:
See the answers below
Explanation:
This problem can be solved by means of the law of conservation of energy, which tells us that the energy between two points is conserved, that is, remains the same.
That is to say, we have two points, the point A where it starts to move and reaches the point B that is 1.5 [m] high, where it stops.
The key to solving this problem is to identify the types of energies at each point. At point A we have kinetic energy and potential energy where the block moves at speed 3 [m/s] at a height of 4 [m]. Whereas at Point B we only have potential energy, since the body is at a height of 1.5 [m], relative to the ground.
a)
Since between the displacement between points A and B there is a friction force, this friction force decreases the final energy in B, in this way the energy or work of the friction will have a negative sign.
Now replacing in the above equation.
b)
We must use the same equation, but this time eliminating the Working term due to friction.
As we can see without friction the block can reach a higher height
25 meters per second.
To find this, divided 150 by 6 in order to get the correct calculation.
Hope this helps!
Answer:
Explanation:
From the information given:
The diameter of the cylindrical heater (d) = 1 cm
The length of the cylindrical heater (l) = 0.25 m
The ambient air temperature = 25° C= (273+25)K = 298 K
The convective heat transfer coefficient (h) = 25 W/m² °C
The electric input Q = 5W
As stated in the question that if radiation is being neglected:-
Let also assume that;
the heat transfer takes place at a steady-state
1-D flow takes place
No external heat generation; &
No force convection takes place;
Then; the heat transfer through the convection can be calculated as:
By solving the above calculation:
T ( surface temperature of the heater) = 50.46° C 122.83° F
Answer:
Part(a): The frequency is .
Part(b): The speed of the wave is .
Explanation:
Given:
The distance between the crests of the wave, .
The time required for the wave to laps against the pier,
The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is .
Also, the time required for the wave for each laps is the time period of oscillation and it is given by .
Part(a):
The relation between the frequency and time period is given by
Substituting the value of in equation (1), we have
Part(b):
The relation between the velocity of a wave to its frequency is given by
Substituting the value of and in equation (2), we have
Answer:
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