R = 4 x + 8y [ Given ]
when ,
x = 4 and R = 32
★ Substituting the values
=> 32 = 4 × 4 + 8y
=> 32 = 16 + 8y
=> 8y = 32 - 16
=> 8y = 16
=> y = 8/16
=> y = 2
Answer:
3
Step-by-step explanation:
4*3=12
3*3=9
5*3=15
So you find the number that can be multiplied or divided by each side the same to get the new number
Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
NEVER HATE MATH!!!
I can’t see the pic , im so sorry
