Discount = 20% of the product price
Discount = 20/100 × $62.50
Discount = $12.5
To best estimate the volume of the log, we assume that the diameter is the average of the diameters at both ends giving us 12 inches as the diameter. Thus, the radius is equal to 0.5 ft. The volume of the log is calculated through the equation,
V = πr²h = π(0.5 ft)²(10 ft) = 7.85 ft³
No they wouldn't be the same because, the perimeter is adding all sides.
The square has 4 sides so you would add 9, four times.
9 + 9 + 9 + 9 = 36
And a pentagon has 5 sides so you would add 9, five times.
9 + 9 + 9 + 9 + 9 = 45
So, they are not the same.
Hope this helps. :)
The ratios are Surface area ⇒ 4 : 25 Height ⇒ 2 : 5 and Volume ⇒ 8 : 125
<h3>How to determine the ratios?</h3>
The scale factor is given as:
m : n = 2 : 5
For the area, we take the square of the ratios.
i.e.
Area = 2^2 : 5^2
Evaluate
Area = 4 : 25
For the volume, we take the cube of the ratios.
i.e.
Volume = 2^3 : 5^3
Evaluate
Volume = 8 : 125
The given scale factor can be used for the height of the model and the original bicycle
Hence, the ratios are
Surface area ⇒ 4 : 25
Height ⇒ 2 : 5
Volume ⇒ 8 : 125
Read more about ratios at:
brainly.com/question/13419413
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<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral.
Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>