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3 years ago

Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

Physics

2 answers:

worty [1.4K]3 years ago

6 0

Answer:Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

Explanation:

laiz [17]3 years ago

5 0

Answer:Whenever the velocity of the object increases or usually doubles, the kinetic energy will be quadrupled. If in case you are not familiar with kinetic energy, this is known as the type of energy that is in motion. The greater the mass of the object, the greater the total of the energy

Explanation:

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the hydrometer with the density of liquid to be 800 kg metre per square is the volume of the submerged part of the hydrometer is

julia-pushkina [17]

Answer:

Mass = 0.04 Kg

Explanation:

Given the following data;

Density = 800 kg/m³

Volume = 5 * 10^{-5} m³

To find the mass of the object;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

$Density = \frac {mass}{volume}$

Making mass the subject of formula, we have;

$Mass = density * volume$

Substituting the values into the formula, we have;

$Mass = 800 * 5 * 10^{-5}$

Mass = 0.04 Kg

8 0

3 years ago

the amount of surface area of the block contact with the surface is 2.03*10^-2*m2 what is the average pressure exerted on the su

CaHeK987 [17]

Complete question:

A block of solid lead sits on a flat, level surface. Lead has a density of 1.13 x 104 kg/m3. The mass of the block is 20.0 kg. The amount of surface area of the block in contact with the surface is 2.03*10^-2*m2, What is the average pressure (in Pa) exerted on the surface by the block? Pa

Answer:

The average pressure exerted on the surface by the block is 9655.17 Pa

Explanation:

Given;

density of the lead, ρ = 1.13 x 10⁴ kg/m³

mass of the lead block, m = 20 kg

surface area of the area of the block, A = 2.03 x 10⁻² m²

Determine the force exerted on the surface by the block due to its weight;

F = mg

F = 20 x 9.8

F = 196 N

Determine the pressure exerted on the surface by the block

P = F / A

where;

P is the pressure

P = 196 / (2.03 x 10⁻²)

P = 9655.17 N/m²

P = 9655.17 Pa

Therefore, the average pressure exerted on the surface by the block is 9655.17 Pa

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3 years ago

Two transverse waves travel along the same taut string. Wave 1 is described by y1(x, t) = A sin(kx - ωt), while wave 2 is descri

Vadim26 [7]

Answer:

6) Wave 1 travels in the positive x-direction, while wave 2 travels in the negative x-direction.

Explanation:

What matters is the part $kx \pm \omega t$ , the other parts of the equation don't affect time and space variations. We know that when the sign is - the wave propagates to the positive direction while when the sign is + the wave propagates to the negative direction, but <em>here is an explanation</em> of this:

For both cases, + and -, after a certain time $\delta t$ ( $\delta t >0$ ), the displacement <em>y</em> of the wave will be determined by the $kx\pm\omega (t+\delta t)$ term. For simplicity, if we imagine we are looking at the origin (x=0), this will be simply $\pm \omega (t+\delta t)$ .

To know which side, right or left of the origin, would go through the origin after a time $\delta t$ (and thus know the direction of propagation) we have to see how we can achieve that same displacement <em>y</em> not by a time variation but by a space variation $\delta x$ (we would be looking where in space is what we would have in the future in time). The term would be then $k(x+\delta x)\pm\omega t$ , which at the origin is $k \delta x \pm \omega t$ . This would mean that, when the original equation has $kx+\omega t$ , we must have that $\delta x>0$ for $k\delta x+\omega t$ to be equal to $kx+\omega\delta t$ , and when the original equation has $kx-\omega t$ , we must have that $\delta x$ for $k\delta x-\omega t$ to be equal to $kx-\omega \delta t$

<em>Note that their values don't matter, although they are a very small variation (we have to be careful since all this is inside a sin function), what matters is if they are positive or negative and as such what is possible or not .</em>

<em />

In conclusion, when $kx+\omega t$ , the part of the wave on the positive side ( $\delta x>0$ ) is the one that will go through the origin, so the wave is going in the negative direction, and viceversa.

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3 years ago

Air pressure increases as you travel higher above sea level. This is the reason that cabins in commercial airliners require pres

irakobra [83]

The answer is true about the cabins in commercial airliners that require pressurization.

<h3>Why are the cabins of commercial airplanes pressurized?</h3>

Airplanes are pressurized because the air is very thin at the high altitude where they fly. The passenger jet has a cruising altitude of about 30,000 - 40,000 feet. At this altitude or height, humans can't breathe very well and our body gets less amount of oxygen. Most aircraft cabins are pressurized to an altitude about 8,000 feet. This is called cabin altitude. Aircraft pilots have access to the control's mode of a cabin pressure control system and if needed it can command the cabin to depressurize.

So we can conclude that cabins in commercial airliners require pressurization because of the greater pressure of the surrounding environment.

Learn more about pressure here: brainly.com/question/28012687

#SPJ1

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1 year ago

Define wheel and axle 4 example of wheel and axle

natita [175]

Answer:

A system of two co-axial cylindersof different diameters which rotate together is called wheel and axle example; the door knob , knob of the tap ,screw driver,water tap

5 0

3 years ago