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padilas [110]
3 years ago
13

How much of a 3.75 M KI solution would you need to prepare 252.5 mL of a 0.780 M KI solution?

Chemistry
1 answer:
saveliy_v [14]3 years ago
4 0
Answer: 52.5 mL

Hope this helps!
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How many moles are found in 133 g of Mg3 N2
konstantin123 [22]
Magnesium nitride weighs 100.95 g/mol

133/100.95 = 1.32 mols
7 0
3 years ago
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reaction 1:CCl4⟶CH4 reaction 2:N2+3H2⟶2H3N reaction 3:2H2+2O2⟶2H2O+Au Which of the chemical reactions are NOT possible according
olga nikolaevna [1]

Clutch Prep

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Solution: Which of the following chemical reactions is/are NOT possible according to Dalton's atomic theory?a. reaction 1: CCl4 → CH4b. reaction 2: N2 + 3H2 → 2NH3c. reaction 3: 2H2 + O2 → 2H2O + Au

Problem

Which of the following chemical reactions is/are NOT possible according to Dalton's atomic theory?

a. reaction 1: CCl4 → CH4

b. reaction 2: N2 + 3H2 → 2NH3

c. reaction 3: 2H2 + O2 → 2H2O + Au

3 0
3 years ago
In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi
mart [117]

The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>
  • Molarity of acid, HCOOH (Ma) = 0.4 M
  • Volume of acid, HCOOH (Va) = 50 mL
  • Molarity of base, LiOH (Mb) = 0.15 M
  • Volume of base, LiOH (Vb) =?

MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

Divide both side by 0.15

Vb = 20 / 0.15

Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

Learn more about titration:

brainly.com/question/14356286

8 0
2 years ago
Each mineral group has a distinctive chemical feature such as
disa [49]

Answer:

A

Explanation:

6 0
2 years ago
Vinegar 59g, Oil 177g, Brown sugar 10g, and total mass
denis-greek [22]

Answer:

Total mass = 246 g

Explanation:

Given data:

Mass of vinegar = 59 g

Mass of oil = 177 g

Mass of brown sugar = 10 g

Total mass = ?

Solution:

Total mass = masses of [sugar + oil + vinegar]

Total mass = 59 g + 177 g + 10 g

Total mass = 246 g

3 0
3 years ago
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