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Sauron [17]
3 years ago
12

Explain how Newton’s second law of motion affects a game of Tug of War

Physics
2 answers:
notka56 [123]3 years ago
8 0

Answer: Newton's second law of motion is F = ma or force is equal to the mass the reason this applies to Newton's third law is because When the game starts, both the sides are pulling the rope and neither side is moving. The force on the rope is the same on each side This is Newton's second law of motion which equates force as mass times acceleration.

Explanation:

cricket20 [7]3 years ago
3 0

Answer:

a force applied to an object at rest causes it to accelerate in the direction of the force

Explanation:

if you tug the rope it goes in your direction when the opposing team does so it goes in their direction. each team pulling on the rope is the force applied to it.

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The element selenium (Se) bonds with chlorine (Cl) to make the formula SeCl2 Chlorine is more electronegative than selenium. Wha
Akimi4 [234]

Answer:

Selenium dichloride

Explanation:

Selenium (Se) and Chlorine (Cl) are both elements capable of combining together to form a compound with the chemical formula; SeCl2. Since the chlorine atom is more electronegative than selenium atom, the chlorine pulls more electrons towards itself to form an IONIC bond.

The SeCl2 compound formed is called Selenium dichloride as two atoms of Chlorine are needed to combine with one atom of Selenium to form the compound.

7 0
3 years ago
Objects in free fall are weightless. true or false???
frez [133]

The answer is false

7 0
3 years ago
HELP
Ivanshal [37]

Answer:

The velocity is 60 km/hr.

Explanation:

<h3><u>Given:</u></h3>

Displacement (d) = 480 km = 48000 m

Time (t) = 8 Hours = 480 minute

Velocity (v) = ?

Now,

Velocity = Displacement ÷ Time

v = d/t

v = 480/8

v = 60 km/hr

Thus, The velocity is 60 km/hr.

<u>-TheUnknownScientist 72</u>

5 0
2 years ago
Which items in this image are electrically conductive? Check all that apply.
balu736 [363]

Answer: a and d

Explanation: A.) the power lines themselves

B.) the wooden pole that supports the lines

C.) the rubber soles on the worker’s boots

D.) the metal tools the worker uses

E.) the wooden ladder leaning against the lines

4 0
3 years ago
A Hall probe, consisting of a rectangular slab of current-carrying material, is calibrated by placing it in a known magnetic fie
Citrus2011 [14]

Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, V_{Hall} = 20\ mV = 0.02\ V

Magnetic Field, B = 0.10 T

Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

where

d = distance

B = \frac{V_{Hall}}{v_{d}sin\theta}                      (2)

(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

5 0
3 years ago
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