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Sauron [17]
3 years ago
12

Explain how Newton’s second law of motion affects a game of Tug of War

Physics
2 answers:
notka56 [123]3 years ago
8 0

Answer: Newton's second law of motion is F = ma or force is equal to the mass the reason this applies to Newton's third law is because When the game starts, both the sides are pulling the rope and neither side is moving. The force on the rope is the same on each side This is Newton's second law of motion which equates force as mass times acceleration.

Explanation:

cricket20 [7]3 years ago
3 0

Answer:

a force applied to an object at rest causes it to accelerate in the direction of the force

Explanation:

if you tug the rope it goes in your direction when the opposing team does so it goes in their direction. each team pulling on the rope is the force applied to it.

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Three capacitors having capacitances of 8.40, 8.40, and 4.20 μFμF, respectively, are connected in series across a 36.0-V potenti
son4ous [18]

Answer:

a)Q=71.4 μ C

b)ΔV' = 10.2 V

Explanation:

Given that

C ₁= 8.7 μF

C₂ = 8.2 μF

C₃ = 4.1 μF

The potential difference of the battery, ΔV= 34 V

When connected in series

1/C = 1/C ₁ + 1/C₂ + 1/C₃

1/ C= 1/8.4 +1 / 8.4 + 1/4.2

C=2.1 μF

As we know that when capacitor are connected in series then they have same charge,Q

Q= C ΔV

Q= 2.1 x 34 μ C

Q=71.4 μ C

b)

As we know that when capacitor are connected in parallel then they have same voltage difference.

Q'= C' ΔV'

C'= C ₁+C₂+C₃        (For parallel connection)

C'= 8.4 + 8.4 + 4.2 μF

C'=21 μF

Q'= C' ΔV'

Q'=3 Q

3 x 71.4= 21 ΔV'

ΔV' = 10.2 V

3 0
3 years ago
A mass m attached to a horizontal massless spring with spring constant k, is set into simple harmonic motion. its maximum displa
Lesechka [4]
At the point of maximum displacement (a), the elastic potential energy of the spring is maximum:
U_i= \frac{1}{2} ka^2
while the kinetic energy is zero, because at the maximum displacement the mass is stationary, so its velocity is zero:
K_i =0
And the total energy of the system is
E_i = U_i+K= \frac{1}{2}ka^2

Viceversa, when the mass reaches the equilibrium position, the elastic potential energy is zero because the displacement x is zero:
U_f = 0
while the mass is moving at speed v, and therefore the kinetic energy is
K_f =  \frac{1}{2} mv^2
And the total energy is
E_f = U_f + K_f =  \frac{1}{2} mv^2

For the law of conservation of energy, the total energy must be conserved, therefore E_i = E_f. So we  can write
\frac{1}{2} ka^2 =  \frac{1}{2}mv^2
that we can solve to find an expression for v:
v= \sqrt{ \frac{ka^2}{m} }
6 0
3 years ago
The fluid friction that opposes the motion of objects through air is known as what?
PSYCHO15rus [73]
The answer is Air Resistance
6 0
4 years ago
Please Help!<br> _______________
marishachu [46]

Answer:

constant at the speed of light

8 0
3 years ago
Dans car has broken down. He decides to push it to a garage 800m away qlong a flat road. He pushes the car with qn average force
Ede4ka [16]

Answer:

Answer = 480000 joule.

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3 0
3 years ago
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