Answer:
E = 10t^2e^-10t Joules
Explanation:
Given that the current through a 0.2-H inductor is i(t) = 10te–5t A.
The energy E stored in the inductor can be expressed as
E = 1/2Ll^2
Substitutes the inductor L and the current I into the formula
E = 1/2 × 0.2 × ( 10te^-5t )^2
E = 0.1 × 100t^2e^-10t
E = 10t^2e^-10t Joules
Therefore, the energy stored in the inductor is 10t^2e^-10t Joules
Answer:
33,458.71 turns
Explanation:
Given: L = 37 cm = 0.37 m, B= 0.50 T, I = 4.4 A, n= number of turn per meter
μ₀ = Permeability of free space = 4 π × 10 ⁻⁷
Solution:
We have B = μ₀ × n × I
⇒ n = B/ (μ₀ × I)
n = 0.50 T / ( 4 π × 10 ⁻⁷ × 4.4 A)
n = 90,428.94 turn/m
No. of turn through 0.37 m long solenoid = 90,428.94 turn/m × 0.37
= 33,458.71 turns
Answer:
Explanation:
We are given that
Mass of spherical shell,=1900 kg
Mass=
Radius of shell=r=5 m
Distance between two masses=r=5.01 m
Because distance measure from center .
Gravitational force
Using the formula
Hence,the gravitational force =
The maximum rate at which energy can be added to the circuit element mathematically given as
<h3>What is the maximum rate at which
energy can be added to the
circuit element?</h3>
Generally, the equation for P is mathematically given as
Therefore
Max temp Change
t=180s
In conclusion, Max Energy Rate
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Answer:
Answer
Explanation:
The very first generation of star systems in the universe probably consisted only of hydrogen and helium. This means that,
There were no comets or asteroids in these first-generation star systems. As the comets and asteroids were the only soruce of elements other than Hydrogen and Heliums ( As starts mainly consists of helium and hydrogen).