By increasing magnification you decrease the field of view.
The answer is A.
Hope this helps.
r3t40
Workers Rights Practice Worksheet Crossword Puzzle OSHA Provides Workers the Right to
1- HAZARDOUS (down)
2- RETALIATION (down)
3- TRAINING (down)
4- EXPOSURE (across)
5- OSHA (down)
6-
7- HEALTHFUL (across)
8- CORRRECTION (across)
9- INSPECTION (across)
<h3>What is workers right?</h3>
Workers' rights are not enumerated or given a single definition. According to the International Labor Organization (ILO), all ILO Members are obligated to uphold and respect certain "fundamental principles and rights at work," including:
Freedom of association, the effective recognition of the right to collective bargaining, the abolition of all forms of forced or compulsory labor, the end of child labor, the eradication of discrimination in employment and occupation, and the creation of a safe and healthy workplace are all guaranteed.
International labor conventions have been adopted in each of these areas, and the ILO oversees their implementation. Although these standards are important, they are not regarded as "fundamental" or "core" conventions because they deal with conditions of work, such as pay and hours.
Learn more about Workers' rights
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Carbon is not used as semiconductor it has 4 valence electrons in it valence shell but the energy gap is very small it will conduct electricity even at room temperature ,the size of carbon is very small .
Answer:
a) 14.285
b) 8.956
Explanation:
Given :
The combustion of the ethanol is with air
Air is 21% oxygen
and, 79% nitrogen
thus, for 1 O₂ we have (79/21)N₂
thus,
the stochiometric equation for the combustion is as:
C₂H₅OH + 3[O₂ + (79/21)N₂] ⇒ 2CO₂ + 3H₂O + 3 × (79/21)N₂
Now,
the molecular weight of the fuel (C₂H₅OH) = (2× 12) + (5 × 1) + 16 + 1 = 46 g/mol
Molecular weight of the air = (2 × 16) + ((79/21) × 28) = 137.33 g/mol
a) air/fuel ratio on a molar basis
we have
air-fuel ratio = moles of air / moles of fuel
or
air-fuel ratio = [3 × 1 + 3 × (79/21)] / 1 = 14.285
b) air/fuel ratio on a mass basis = Mass of air / mass of fuel
or
air/fuel ratio on a mass basis = (number of moles of air × molar mass of air) / (number of moles of fuel × molar mass of fuel)
on substituting the values, we have
air/fuel ratio on a mass basis = (3 × 137.33) / (1 × 46) = 8.956
Answer:
3180.86 Nm
Explanation:
Moment of inertia for shaft AB,
Torque in solid shaft AB will be given by
Where is shear stress, is polar moment of inertia for shaft AB, r is the radius of shaft B
The inner diameter of pipe CD can found considering that the thickness of pipe is 0.006 m hence diameter= 0.09-(2*0.006)= 0.078 m
Moment of inertia for shaft CD will be
Torque for shaft CD will be
and here r = 0.045 m
The minimum of the two torques is the largest torque that can be applied. Therefore, the torque to apply equals 3180.86 Nm