For the excited state of Ca at the absorption of 422.7 nm light,the energy difference is mathematically given as
E= 4.70x10-22 kJ/mol
<h3>What is the energy difference (kJ/mole) between the ground and the first excited state?</h3>
Generally, the equation for the Energy is mathematically given as
E = nhc / λ
Where
h= plank's constant
h= 6.625x 10-34 Js
c = speed of light
c= 3x 108 m/s
Therefore
E = 1*(6.625x 10-34 Js)( 3x 10^8 m/s) / ( 422.7x10^-9)
E= 4.70x10-22 kJ/mol
In conclusion, Energy
E= 4.70x10-22 kJ/mol
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Answer:
The amount is 
Explanation:
From the question we are told that
The distance traveled per day is 
The cost of one liter is 
The car's gas mileage is 
Generally the amount of distance covered in one week is evaluated as


The amount of gas used in one week by the car is mathematically represented as

=> 
=> 
converting to liters

Thus the amount spent on gas in one week is

=> 
=> 
It's what you put :)
ΔH is the distance from the reactants (which would be E), to the products (which would be G or D)