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baherus [9]
3 years ago
12

25.0 g of mercury is heated from 25°C to 155°C, and absorbs 455 joules of heat in the

Physics
1 answer:
anastassius [24]3 years ago
5 0

Answer:

0.048J/g°C

Explanation:

Given parameters:

Mass of Mercury  = 25g

Initial temperature  = 25°C

Final temperature  = 155°C

Amount of heat absorbed  = 455J

Unknown:

Specific heat capacity of mercury  = ?

Solution:

To solve this problem, we use the expression below:

      Q  = m x C  x Δt

Q is the heat absorbed

m is the mass

C is the unknown specific heat capacity

Δt is the change in temperature;

          455  = 25 x C x (155  - 25)

          455  = 25 x C x 130

             C  = 0.048J/g°C

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Winding the spring of a clock is what type of energy
NeTakaya

Answer:

potential energy

Answer : During the winding of the spring of a clock, the kinetic energy gets converted into stored potential energy of the spring.

7 0
3 years ago
A hot iron horseshoe (mass = 0.35 kg ), just forged, is dropped into 1.40 L of water in a 0.45 kg iron pot initially at 22.0°C.
olga_2 [115]

Answer:

420 °C

Explanation:

m_{h} = mass of the horseshoe = 0.35 kg

m_{w} = mass of the water = 1.40 L = 1.40 kg

m_{i} = mass of the iron pot = 0.45 kg

c_{i} = specific heat of iron = 450 J kg⁻¹ °C⁻¹

c_{w} = specific heat of water = 4186 J kg⁻¹ °C⁻¹

T_{hi} = initial temperature of the horseshoe = ?

T_{wi} = initial temperature of the water = 22 °C

T_{pi} = initial temperature of the iron pot = 22 °C

T_{f} = final temperature = 32 °C

Using conservation of Heat

m_{h}c_{i}(T_{hi} - T_{f}) = m_{w}c_{w}(T_{f} - T_{wi}) + m_{i}c_{i}(T_{f} - T_{pi})

(0.35)(450)(T_{hi} - 32) = (1.40)(4186)(32 - 22) + (0.45)(450)(32 - 22)

(157.5)(T_{hi} - 32) = 60629

T_{hi} - 32 = 384.95

T_{hi} = 420 °C

7 0
3 years ago
Two conducting spheres of different sizes are at the same potential. The radius of the larger sphere is four times larger than t
Sergeeva-Olga [200]

Answer:

0.8

Explanation:

The two spheres have the same potential, V.

Let the radius of the larger sphere be R and the radius of the smaller sphere be r,

=> R = 4r

Let the charge on the smaller sphere be q. Hence, the larger sphere will have charge Q - q.

The potential of the smaller sphere will be:

V_S = \frac{kq}{r}

The potential of the larger sphere will be:

V_L = \frac{k(Q - q)}{R}

Inputting R = 4r,

V_L = \frac{k(Q - q)}{4r}

Since V_S = V_L = V,

\frac{k(Q - q)}{4r} = \frac{kq}{r}

=> Q - q = 4q

=> 5q = Q

q = 0.2Q

The fraction of the charge Q that rests on the smaller sphere is 0.2

The charge of the larger sphere is:

Q - q = Q - 0.2Q = 0.8Q

∴ The fraction of the total charge Q that rests on the larger sphere is 0.8

7 0
4 years ago
Which of the following is MOST useful to scientists in measuring the size of asteroids?
Alenkasestr [34]

Answer:c-The gravitational effect when spacecraft flies close to the asteriod

Explanation:

Gravitational effect on the spacecraft gives an estimate that how big is the asteroid by experiencing its gravitational pull.

The amount of extra thrust required to maintain the trajectory of the spacecraft during its motion hints at the scientist about the size of the asteroid.

Gravitational pull is directly proportional to the mass of object so greater the mass, greater will be the pull.

5 0
3 years ago
Water waves are caused by wind, which is caused by the sun
11Alexandr11 [23.1K]

The sun emits electromagnetic radiation so I think they are electromagnetic waves.

3 0
3 years ago
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