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Illusion [34]
2 years ago
11

H. A truck starts to move from rest. If it gains the acceleration of 3 m/s2 in 5 sec,

Physics
1 answer:
SashulF [63]2 years ago
6 0

Answer:

1. The final velocity of the truck is 15 m/s

2. The distance travelled by the truck is 37.5 m

Explanation:

1. Determination of the final velocity

Initial velocity (u) = 0 m/s

Acceleration (a) = 3 m/s²

Time (t) = 5 s

Final velocity (v) =?

The final velocity of the truck can be obtained as follow:

v = u + at

v = 0 + (3 × 5)

v = 0 + 15

v = 15 m/s

Therefore, the final velocity of the truck is 15 m/s

2. Determination of the distance travelled

Initial velocity (u) = 0 m/s

Acceleration (a) = 3 m/s²

Time (t) = 5 s

Distance (s) =?

The distance travelled by the truck can be obtained as follow:

s = ut + ½at²

s = (0 × 5) + (½ × 3 × 5²)

s = 0 + (½ × 3 × 25)

s = 0 + 37.5

s = 37.5 m

Therefore, the distance travelled by the truck is 37.5 m

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Answer:

Explanation:

Use the one-dimensional equation

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Δx = -2 (negative because where it ends up is lower than the point at which it started),

v_0=5, and

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Filling in:

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this should look hauntingly familiar (a quadratic, which is parabolic motion...very important in physics!!). We begin by getting everything on one side of the equals sign and solving for t by factoring:

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When you factor this however your math/physics teacher has you factoring you will get that

t = 1.3 sec and t = -.31 sec

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Answer:

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Explanation:

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