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2 years ago

H. A truck starts to move from rest. If it gains the acceleration of 3 m/s2 in 5 sec,

Physics

1 answer:

SashulF [63]2 years ago

6 0

Answer:

1. The final velocity of the truck is 15 m/s

2. The distance travelled by the truck is 37.5 m

Explanation:

1. Determination of the final velocity

Initial velocity (u) = 0 m/s

Acceleration (a) = 3 m/s²

Time (t) = 5 s

Final velocity (v) =?

The final velocity of the truck can be obtained as follow:

v = u + at

v = 0 + (3 × 5)

v = 0 + 15

v = 15 m/s

Therefore, the final velocity of the truck is 15 m/s

2. Determination of the distance travelled

Initial velocity (u) = 0 m/s

Acceleration (a) = 3 m/s²

Time (t) = 5 s

Distance (s) =?

The distance travelled by the truck can be obtained as follow:

s = ut + ½at²

s = (0 × 5) + (½ × 3 × 5²)

s = 0 + (½ × 3 × 25)

s = 0 + 37.5

s = 37.5 m

Therefore, the distance travelled by the truck is 37.5 m

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gulaghasi [49]

Answer:

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Explanation:

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The velocity is, by definition: $v=\frac{dx}{dt}$ , so

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This velocity remains constant in the section 2, so for that section the movement equation is:

$x=v*t\\t=\frac{x}{v}$

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$t=\frac{89}{6.2225}=14.303s$

So, the total time is 14.303+3.5355s=17.838s

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3 years ago

An environmental scientist gives a demonstration on composting. Roger is in the audience. He wonders how composting discarded fo

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3 years ago

Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m

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1.034m/s

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