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3 years ago

Current in a circuit is measured by an?

Physics

1 answer:

Rom4ik [11]3 years ago

3 0

Answer:

An ammeter.

Explanation:

The electric current in one part of a circuit is measured with an ammeter, which gives a reading in ampere.

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A pulley system has an MA of 4. How much force would be necessary to pull a 200 newton box

Airida [17]

Mechanical advantage is defined as

$MA = \frac{F_{output}}{F_{input}}$

MA = 4

now we will have

$F_{output} = 200 N$

as we need to pull up a box of weight 200 N

now by above formula we can find how much force it requires to pull up the box

$4 = \frac{F_{output}}{F_{input}}$

$4 = \frac{200}{F_{input}}$

$F_{input} = \frac{200}{4} = 50 N$

so it requires 50 N force to pull the weight of 200 N

7 0

3 years ago

Mechanical waves apply________to push molecules in their path? <br> (fill in the blank)

Alex

Answer:

what is the force of gravitational attraction between an object with a mass of 100 kg and another object that has a mass of 300 kg are at a distance of 2m apart

6 0

3 years ago

Fill in the blanks to complete each statement about metamorphic rocks.

kap26 [50]

Answer:

1) MANTLE 2) MAGMA 3) MINERALS

Explanation:

I just did the assignment and got it correct hope this helps

3 0

3 years ago

Read 2 more answers

How many atoms are present in 3 moles of chromium? A. 1.80 x 1023 atoms B. 6.02 x 1023 atoms C. 52.0 atoms D. 1.80 x 1024 atoms

Anton [14]

1.80 * 10^24 atoms is the answer your looking for.

6 0

3 years ago

Honeybees acquire a charge while flying due to friction with the air. A 120 mg bee with a charge of + 23 pC experiences an elect

Alex Ar [27]

Answer:

$\frac{F}{W}=1.95\times10^{-6}$

$51304447 \frac{N}{C}$

Upward

Explanation:

The weight of the bee is:

$W=mg=(120\times10^{-6}kg)(9.81\frac{m}{s^{2}})=1.18\times10^{-3}N$

with m the mass and g the gravity acceleration.

Electric force of the bee is related with the electric field of earth by:

$F_{e}=qE=(23\times10^{-12}C)(100\frac{N}{C})=2.3\times10^{-9}$

with q the charge, E the electric field and Fe the electric force.

So:

$\frac{F}{W}=\frac{2.3\times10^{-9}}{1.18\times10^{-3}}=1.95\times10^{-6}$

Because Newton's first law we should make the net force on it equals cero:

$F+F_e+W=0$

$F=-(F_e+W)=-(2.3\times10^{-9} +1.18\times10^{-3})=-1.1800023\times10^{-3}$

with W the weight, Fe the electric force on the bee due earth's electric field and F the force.

So, the applied electric field should be:

$E_a=\frac{-1.1800023\times10^{-3}}{23\times10^{-12}}=-51304447 \frac{N}{C}$

The negative sign indicates that the electric field should be opposite to earth's electric field, so it should be upward.

7 0

4 years ago