The number of solid precipitate that will be formed is 37.08 g
calculation
write the equation for reaction
=Hg(NO3)2 +Na2SO4 = HgSO4(s) +2NaNO3(aq)
find the moles of each reactant
moles ofHg(NO3)2=126.27/324.6= 0.389 moles
moles of Na2SO4=17.796/142=0.125 moles
NaSO4 is the limiting reagent and by use of mole ratio of NaSO4:HgSO4 which is 1:1 therefore the moles of H2SO4 is also= 0.125 moles
mass HgSO4=moles x molar mass
=0.125 x296.65= 37.08g
Sodium azide is a colorless inorganic salt that can decompose to give sodium and nitrogen. It is an ionic compound and it is very soluble in water, but it is very toxic. The decomposition reaction usually take place at a very high temperature of 300 degree Celsius under controlled conditions. The equation for the chemical reaction is given below:
2NaN3 = 3N2 + 2Na
Decreasing the activation energy needed for the reaction.
Answer:
Doing push-ups
Explanation:
When you workout you get hot so the tempeture of ur body increase.
Explanation:
The chemical reaction equation will be as follows.
In this reaction, 1 mole of reacts with 3 mole NaOH. So, the number of moles of present in 150 ml of 0.1 M solution is calculated as follows.
No. of moles =
= 0.015 mol
As it reacts with 3 moles of NaOH. Hence, no.. of moles of NaOH are:
= 0.045 mol
So, moles of NaOH in 400 of 0.2 M NaH is as follows.
No. of moles =
= 0.080 mol
Hence, no. of moles remained after the reaction are as follows.
(0.080 - 0.045) mol
= 0.035 mol NaOH in 550 ml (400 ml + 150 ml)
As molarity is the no. of moles present in liter of solution. Hence, molarity of NaOH is as follows.
Molarity =
=
= 0.0636 M
As, = 0.0636 M. Hence, pOH will be 1.20.
As, pH + pOH = 14
pH = 14 - pOH
= 14 - 1.20
= 12.80
Also,
So,
= M
Thus, we can conclude that pH of the given solution is 12.80 and its hydrogen ion concentration is M.