Answer:
M = 1433.5 kg
Explanation:
This exercise is solved using the Archimedean principle, which states that the hydrostatic thrust is equal to the weight of the desalinated liquid,
B = ρ g V
with the weight of the truck it is in equilibrium with the push, we use Newton's equilibrium condition
Σ F = 0
B-W = 0
B = W
body weight
W = M g
the volume is
V = l to h
rho_liquid g (l to h) = M g
M = rho_liquid l a h
we calculate
M = 1000 4.7 6.10 0.05
M = 1433.5 kg
I think the answer to your question is twenty-four percent.
Answer: Option (a) is the correct answer.
Explanation:
AC current stands for alternating current. In an alternating current there is periodically reverse movement of current.
This means electrons move in one direction for a certain time and then they reverse their movement for the same time period and it continues in the back and forth position.
Thus, we can conclude that the statement electrons move back and forth is true regarding AC current.
Answer:
(a) 1294.66 m
(b) 88.44°
Explanation:
d1 = 580 m North
d2 = 530 m North east
d3 = 480 m North west
(a) Write the displacements in vector forms
![\overrightarrow{d_{1}}=580\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B1%7D%7D%3D580%5Cwidehat%7Bj%7D)
![\overrightarrow{d_{2}}=530\left ( Cos45\widehat{i}+Sin45\widehat{j} \right )](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B2%7D%7D%3D530%5Cleft%20%28%20Cos45%5Cwidehat%7Bi%7D%2BSin45%5Cwidehat%7Bj%7D%20%5Cright%20%29)
![\overrightarrow{d_{2}}=374.77\widehat{i}+374.77\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B2%7D%7D%3D374.77%5Cwidehat%7Bi%7D%2B374.77%5Cwidehat%7Bj%7D)
![\overrightarrow{d_{3}}=480\left ( - Cos45\widehat{i}+Sin45\widehat{j} \right )](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B3%7D%7D%3D480%5Cleft%20%28%20-%20Cos45%5Cwidehat%7Bi%7D%2BSin45%5Cwidehat%7Bj%7D%20%5Cright%20%29)
![\overrightarrow{d_{3}}=-339.41\widehat{i}+339.41widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B3%7D%7D%3D-339.41%5Cwidehat%7Bi%7D%2B339.41widehat%7Bj%7D)
The resultant displacement is given by
![\overrightarrow{d}\overrightarrow{d_{1}}+\overrightarrow{d_{2}}+\overrightarrow{d_{3}}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd%7D%5Coverrightarrow%7Bd_%7B1%7D%7D%2B%5Coverrightarrow%7Bd_%7B2%7D%7D%2B%5Coverrightarrow%7Bd_%7B3%7D%7D)
![\overrightarrow{d}=\left ( 374.77-339.41 \right )\widehat{i}+\left ( 580+374.77+339.41 \right )\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd%7D%3D%5Cleft%20%28%20374.77-339.41%20%5Cright%20%29%5Cwidehat%7Bi%7D%2B%5Cleft%20%28%20580%2B374.77%2B339.41%20%5Cright%20%29%5Cwidehat%7Bj%7D)
![\overrightarrow{d}=35.36\widehat{i}+1294.18\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd%7D%3D35.36%5Cwidehat%7Bi%7D%2B1294.18%5Cwidehat%7Bj%7D)
magnitude of the displacement
![d ={\sqrt{35.36^{2}+1294.18^{2}}}=1294.66 m](https://tex.z-dn.net/?f=d%20%3D%7B%5Csqrt%7B35.36%5E%7B2%7D%2B1294.18%5E%7B2%7D%7D%7D%3D1294.66%20m)
d = 1294.66 m
(b) Let θ be the angle from + X axis direction in counter clockwise
![tan\theta =\frac{1294.18}{35.36}=36.6](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cfrac%7B1294.18%7D%7B35.36%7D%3D36.6)
θ = 88.44°
Answer : The correct option is, (D) A machine does 400 joules of work in 5 seconds.
Explanation :
Power : It is defined a the rate of doing work per unit time.
Formula used :
![P=\frac{w}{t}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7Bw%7D%7Bt%7D)
where,
P = power
w = work done
t = time
Now we have to determine the rate of power for the following options.
(A) A machine does 200 joules of work in 10 seconds.
![P=\frac{200}{10}=20W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B200%7D%7B10%7D%3D20W)
(B) A machine does 400 joules of work in 10 seconds.
![P=\frac{400}{10}=40W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B400%7D%7B10%7D%3D40W)
(C) A machine does 200 joules of work in 5 seconds.
![P=\frac{200}{5}=40W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B200%7D%7B5%7D%3D40W)
(D) A machine does 400 joules of work in 5 seconds.
![P=\frac{400}{5}=80W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B400%7D%7B5%7D%3D80W)
From this we conclude that, a machine does 400 joules of work in 5 seconds has the highest rate of power.
Hence, the correct option is, (D)