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Citrus2011 [14]

3 years ago

15

[H] = 1.00 x 10^-7 M a. Acidic b. Basic c. Neutral

1 answer:

user100 [1]3 years ago

8 0

The answer would be A

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How is the water cycle realated to weather patterns and climate? Make sure to put 2 evidences

Setler79 [48]

When there’s water in a department such as a lake, pound or/and ocean, the water tends to evaporated into the air and that’s how/when clouds are created. The same water from those locations are the same water that comes from the rain water, it’s a cycle that creates and takes water

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3 years ago

How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.

Gekata [30.6K]

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

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3 years ago

Adam is trying to identify a solid. He places a small amount of the substance in an acid solution and observes whether or not a

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3 years ago

A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0

4 years ago