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lilavasa [31]
3 years ago
5

When an atom in a reactant loses electrons, what happens to its oxidation number?

Chemistry
2 answers:
Anton [14]3 years ago
5 0
Its oxidation number increases. When an atom loses electrons, there are now more protons then electrons so its oxidation number increases.
Hope this helps
Marta_Voda [28]3 years ago
4 0

Its oxidation number increases. When an atom loses electrons, there are now more protons then electrons so its oxidation number increases.

Explanation:

The oxidation product of an element signifies the hypothetical charge of an atom in a compound. It is hypothetical because, in the context of a compound, the elements may not absolutely be ionic. When the number of electrons associated with an atom changes, its oxidation number also changes. When an element loses an electron, its oxidation number rises.

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A cylinder with a moveable piston contains 0.552 mol of gas and has a volume of 259 mL . Part A What will its volume be if an ad
Naddik [55]

Answer:

The new volume will be 367mL

Explanation:

Using PV = nRT

V1 = 259mL = 0.000259L

n1 = 0.552moles

At constant temperature and pressure, the value is

P * 0.000259 = 0.552 * RT ------equation 1

= 0.552 / 0.000259

= 2131.274

V2 = ?

n2 = 0.552 + 0.232

n2 = 0.784mole

Using ideal gas equation,

PV = nRT

P * V2 = 0.784 * RT ---------- equation 2

Combining equations 1 and 2 we have;

V2 = 0.784 / 2131.274

V2 = 0.000367L

V2 = 367mL

7 0
3 years ago
I what process does a solid change directly into a vapor​
Marina86 [1]

Answer:

solid change directly into a vapor in the process known simply as freezing

7 0
3 years ago
Three of Louis Pasteur discovery
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Pasteurization, vaccines against antrax and rabies, discovered the germ fermentation
7 0
3 years ago
If element x forms the oxides xo and x2o3 the oxidation numbers of element x are
Deffense [45]

Answer:

b) +2 and +3.

Explanation:

Hello,

In this case, given the molecular formulas:

XO

And:

X_2O_3

We can relate the subscripts with the oxidation states by knowing that they are crossed when the compound is formed, for that reason, we notice that oxygen oxidation state should be -2 for both cases and the oxidation state of X in the first formula must be +2 since both X and O has one as their subscript as they were simplified:

X^{+2}O^{-2}

Moreover, for the second case the oxidation state of X should be +3 in order to obtain 3 as the subscript of oxygen:

X_2^{+3}O_3^{-2}

Thus, answer is b)+2 and +3

Best regards.

3 0
2 years ago
In the second step of this reaction, isocyanic acid reacts to form melamine and carbon dioxide: hnco(l)→c3n3(nh2)3(l)+co2(g) bal
slava [35]

Formula of isocyanic acid is HNCO. It colourless, volatile compound. It is poisonous inorganic compound. Melamine is synthesized from urea. The reaction involves two steps. In first step, urea gets converted to isocyanic acid  which is an intermediate. In the second step, isocyanic acid gives melamine (molecular formula C₃H₆N₆) and carbon dioxide (CO₂). The balanced chemical reaction involved in second step is given below:

6 HNCO → 1 C₃N₃(NH₂)₃ + 3CO₂

The co-efficient of the reaction are: 6, 1, 3

7 0
3 years ago
Read 2 more answers
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