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ololo11 [35]
3 years ago
11

You bought a magazine for 6 dollars and three candy bars you spend a total of 12 dollars how much did each candy cost?

Mathematics
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

$2

Step-by-step explanation:

step 1: 12-6=6

Step2: 6 divided by 3

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Which number is a reasonable estimate for the sum of the equation 1,956 + 1,183 = ________?
jonny [76]

Answer:

3,139

Step-by-step explanation:

1,956 + 1,183 = 3,139

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Hello!

Let's make each of these ratios have a common denominator of 36.

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Which of the following is the solution set of the given equation? 14 + 8m = 14 - 3m - 5m ∅ {0} {all reals}
Yanka [14]

Answer:

{0}

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14 + 8m = 14 - 3m - 5m

Combine like terms

14 + 8m = 14 - 8m

Add 8m to each side

14 +8m +8m = 14 -8m +8m

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Subtract 14 from each side

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Please someone help me solve this i dpnt know the answer​
kozerog [31]
<h2><u>Answer With Explanation:</u></h2>

<u>Firstly, let's start with <XOZ: =55°</u>

We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)

<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>

These 2 angles are joined to create an equilateral triangle which always adds up to 180°

So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°

<u>Thirdly, <QON: =55°</u>

This angle lies on the line XON which needs to add up to 180°

As we worked out before, <XOZ was 55°

So, <ZOQ was already given as 70°

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<QON is 55°

(I'm only in Grade 9 LOL)

4 0
2 years ago
In the beginning of the study, a randomly selected group of 121 students scored an average of 252 words per minute on the readin
Alborosie

Answer:

Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M will be approximately normal.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a sample size larger than 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

So

Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M will be approximately normal.

5 0
3 years ago
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