Question

The monovalent salt concentration (the predominant solute in the blood cell) for a sample of red blood cells is 0.13 moles/liter. If one of these red blood cells were placed in pure water (at around room temperature, 300 K), and the cell comes to hydrostatic equilibrium with the water, what is the osmotic pressure of the cell (assuming it doesn't burst)

Answer 1

Answer:

The osmotic pressure of cell is $648.3$ KPa

Explanation:

As we know the osmotic pressure is equal to

$\pi = icRT$

Where

i is the Van Hoff factor

c is the concentration of solution

R is the ideal gas constant

and T is the temperature.

Substituting the given values, we get -

$\pi = 2 * 0.13 * 0.08206 * 300$

$\pi = 648.3$ KPa